1 / 12

THIS IS a ripoff of JEOPARDY!

THIS IS a ripoff of JEOPARDY!. THIS IS a ripoff of JEOPARDY!. Trig Equations (1 min). Solve for 0 ≤ θ ≤ 2 π : sin θ + 1 = 0. Trig Graphs (1 min). Identify the amplitude and period of the function f ( x ) = 8 + 3.2sin(4 x ). Trig Graphs (2 min).

elon
Télécharger la présentation

THIS IS a ripoff of JEOPARDY!

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. THIS ISa ripoff of JEOPARDY!

  2. THIS ISa ripoff of JEOPARDY!

  3. Trig Equations (1 min) Solve for 0 ≤ θ ≤ 2π : sinθ + 1 = 0

  4. Trig Graphs (1 min) Identify the amplitude and period of the function f(x) = 8 + 3.2sin(4x)

  5. Trig Graphs (2 min) Sketch the function g(x) = 7cos(x) + 2 Include at least 2 full periods.

  6. Trig Equations (3 min) Solve for 0 ≤ θ ≤ 2π : 2sin2θ– 1 = 0

  7. * Trig Graphs (2 min) Identify the max and min values of the function f(x) = 4 – 5sin(3πx) max = 9 min = -1

  8. Trig Graphs (2 min)

  9. Trig Equations (1 min)

  10. Let W(t) = 120 – 26sin(πt/12), 1 < t < 31 represent Mr. Chute’s weight over the month of October, with weight measured in lbs and t measured in days. What is the difference in Mr. Chute’s weight between October 6 and October 14? Trig Graphs (4 min) Oct 6: 94 lbs; Oct 14: 133 Thus difference in weight is 39 lbs.

  11. Trig Equations (3 min) Solve for theta on that interval… 2cos2t + sint – 1 = 0 θ = π/3, π, 5π/3

  12. Trig Graphs (3 min) Let s(t) = 4.8cos(π(x + 2)/2) be the horizontal position of a student on a swing, with a negative value denoting a position on the left and vice versa; t is measured in seconds and s(t) is measured in ft. At t = 8, is the student at a left or right position, and how far to the left or right is the student? Student is on the left by 4.8 feet.

More Related