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Nutritional Analysis and Heat Release Calculation for Pretzel Ingredients

This analysis focuses on the caloric and heat properties of pretzel ingredients, particularly aluminum and water. With an initial temperature of 22°C and a final temperature of 48°C, the heat released during the heating of the mixture is calculated based on the masses of aluminum (27.65g) and water (96.54g). The method includes evaluating specific heat capacities and temperature changes, illustrating the energetic transformations occurring in the system. This data is crucial for understanding the nutritional and caloric content of pretzels.

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Nutritional Analysis and Heat Release Calculation for Pretzel Ingredients

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  1. Nut Calories – Pretzel Calories

  2. Nut Calories – Pretzel Calories Mass = 4.12g

  3. Nut Calories – Pretzel Calories Mass = 4.12g Mass Al Cup= 27.65 g

  4. Nut Calories – Pretzel Calories Mass = 4.12g Mass of Al and water = 96.54g

  5. Nut Calories – Pretzel Calories Mass = 4.12g Mass of Al and water = 96.54g

  6. Nut Calories – Pretzel Calories Mass = 4.12g Mass of Al and water = 96.54g Initial Temp =22 oC

  7. Nut Calories – Pretzel Calories Mass = 4.12g Heat Mass of Al and water = 96.54g Initial Temp 22 C

  8. Nut Calories – Pretzel Calories Mass = 4.12g Heat Mass of Al and water = 96.54g Initial Temp 22 C

  9. Nut Calories – Pretzel Calories Mass of Al and water = 96.54g Initial Temp 22 oC Mass = 4.12g Heat

  10. Nut Calories – Pretzel Calories Mass of Al and water = 96.54g Initial Temp 22 oC Mass = 4.12g Heat

  11. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat

  12. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =

  13. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change)

  14. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change) ( mass of water)

  15. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)

  16. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)

  17. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)

  18. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)

  19. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released =( water temp change)( mass of water)(H2Ospecific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)

  20. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +

  21. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +

  22. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +

  23. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +

  24. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C)

  25. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))

  26. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))

  27. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))

  28. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cal / g C))

  29. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal

  30. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal

  31. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal

  32. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal / 4.12 g =

  33. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal / 4.12 g =

  34. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal =461.16 cal/g 4.12 g

  35. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal =461.16 cal/g=4.6x102cal/g 4.12 g

  36. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal / 4.12 g = 461 cal / g=4.6x102cal/g 461 cal/g ( 1 kcal / 1000 cal ) = .46 kcal

  37. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat Heat released per gram = 1.9 x103 cal / 4.12 g = 461 cal / g 461 cal/g ( 1 kcal / 1000 cal ) = .46 kcal Accepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g

  38. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat 461 cal/g ( 1 kcal / 1000 cal ) = .46 kcal Accepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g % difference = (experimental – accepted ) / accepted * 100

  39. Nut Calories – Pretzel Calories Mass of Al =27.65g Mass of Al and water = 96.54g Initial Temp 22 oC Final Temp = 48oC Mass = 4.12g Heat 461 cal/g ( 1 kcal / 1000 cal ) = .46 kcal Accepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g % difference = (experimental – accepted ) / accepted * 100 % = (.46 Kcal/g -3.9 Kcal/g ) / 3.9 kcal/g * 100 = - 88 %

  40. Results: The following data can be used to:

  41. .Calculations / Conclusions • 1. The heat released by the nut was absorbed by the Water and the Al cup. • The amount of energy absorbed by a substance is dependent on its specific heat capacity, its mass , and its temperature change. • Q= (mwDtw * 1 cal / g oC) + (mAlDtAl * .21 cal / g oC) • Q = (90.76g – 19.83g) (68.8oC– 21.2oC) ( 1 cal/g oC) + • ((19.83g) (68.8oC– 21.2oC) ( .21 cal/g oC)) • Q= 3574.48 cal 3570 cal  3.57x103 cal • 2. Determine the number of calories per gram of food burned. • cal = 3570 cal = 2664.179 cal / g  2.66x103cal/g • g (1.34g )

  42. 3. Convert the number of calories per gram to Calories or kcal per gram. 2.66x103cal/g ( 1 kcal) = 2.66 kcal / g (1000cal) 4. Convert the number of cal per gram to J per gram. 2.66x103cal/g ( 4.18 J) = 11,118.8 J / g  1.11x104 J/g ( 1 cal) 5. Convert the number of cal per gram to KJ per gram 1.11x104 J/g ( 1 KJ ) = 11.1 KJ/g (1000 J)

  43. 6. According to the packaging the nut should release 250 kcal per 42 grams.(cashews) =5.95kcal/g a) What is your percent error in your experiment? % error = ( your value – accepted value ) * 100 = ( accepted value ) % error = (2.66 kcal/g – (5.95kcal/g))*100 = -55.3% error (5.95 kcal/g )

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