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Division Methods

Division Methods. By Erin James. The first method to solve long division is to try dividing each section of the original number by the dividing number, separately. For example: 14| 3 67 First you try 14 into 3 but this is not possible . 14| 36 7

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Division Methods

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  1. Division Methods By Erin James

  2. The first method to solve long division is to try dividing each section of the original number by the dividing number, separately. For example: 14|367 First you try 14 into 3 but this is not possible. 14|367 So next you try 14 into 36 which = 2 r8 2 14|3687 Next you put the 8 with the 7 to make 87 and do 14 into 87 = 6r3 26 r3 14|367 So the answer = 26 r3

  3. Another example is: 9|436 First you try 9 into 4but this is not possible. 9|436 So next you try 9 into 43which = 4 r7 4 9|4376 Next you put the 7 with the 6 to make 76 and do 9 into 76= 8 r4 48 r4 9|436 So the answer = 48 r4

  4. The other way of doing long division is the chunking method. First of all you need to write down the 1st 10 multiples of 14: 1x14 = 14 6x14 = 84 2x14 = 28 7x14 = 98 3x14 =42 8x14 = 112 4x14 = 56 9x14 = 126 5x14 = 70 10x14 = 140 You can also imagine these numbers multiplied by 10 (e.g. 20x14 = 280, 30x14 = 420 etc.) Now, when you look at the number 367 you can see that 20x14 (280) will go into it but not 30x14(420) so the first number =20. Next you subtract the 280 from the original number 367 (367 – 280 = 87) You can see from the 14 times table that 6x14 will go into 87 but not 7x14(98) so the next number must be 6 Now you subtract 6x14 (84) from the 87 (87-84 = 3). As 14 won’t go into 3 at all then this must be the remainder. Finally you add the numbers together 20 + 6 + r3 giving the answer 26 r3

  5. Here is the 2nd example solved by the chunking method. First of all you need to write down the 1st 10 multiples of 9: 1x9 = 96x9 = 54 2x9 = 187x9 = 63 3x9 = 278x9 = 72 4x9 = 369x9 = 81 5x9 = 4510x9 = 90 You can also imagine these numbers multiplied by 10 (e.g. 20x9 = 180, 30x9 = 270, 40x9 = 360, 50x9 = 450etc.) Now, when you look at the number 436 you can see that 40x9 (360) will go into it but not 50x9(450) so the first number =40. Next you subtract the 360from the original number 436 (436 – 360= 76) You can see from the 9 times table that 8x9 will go into 76 but not 9x9(81) so the next number must be 8 Now you subtract 8x9 (72) from the 76 (76-72= 4). As 9 won’t go into 4at all then this must be the remainder. Finally you add the numbers together 40+ 8+ r4giving the answer 48 r4

  6. This is the end of my “Division Methods” presentation. I hope you enjoyed and understood it.

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