1 / 10

Advanced Alg – Unit One Data Analysis

This guide explains how to find the Z-score of a given data point and how to utilize it in statistics. Z-scores indicate how many standard deviations a data point is from the mean, helping in understanding data distribution. This resource outlines step-by-step procedures to calculate Z-scores using mean and standard deviation, with real-world examples for clarity. Learn how to find data values that correspond to specific percentages and analyze their significance in relation to their mean.

gwydion-probert
Télécharger la présentation

Advanced Alg – Unit One Data Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Advanced Alg– Unit OneData Analysis Finding data that will give z-score

  2. Z Score z score = Data – Mean σ σ: standard deviation Gives exact standard deviation of a piece of data.

  3. Find the z score Given: Data = 93 Mean = 90 σ = 2 z score = (93 – 90) ÷ 2 = 1.5 1.5 σ above the mean

  4. Find the data that will give z-score Steps Use percent to find z-score Find mean and σ Plug into formula and solve for data

  5. Given: Mean of 96 and σ = 7Find: Find data that shows less that 72% 72% = a z-score of .58 .58 = (D – 96)/ 7 7(.58) = D – 96 4.06 = D – 96 D = 4.06 + 96 D = 100.06

  6. Given: Mean of 96 and σ = 7Find: Find data that shows less that 20% 20% = a z-score of -.85 -.85 = (D – 96)/ 7 7(-. 85) = D – 96 -5.95 = D – 96 D = -5.95 + 96 D = 90.05

  7. Given: Mean of 96 and σ = 7Find: Find data that shows less that 98% 98% = a z-score of 2.05 2.05 = (D – 96)/ 7 7(2.05) = D – 96 14.35 = D – 96 D = 14.35 + 96 D = 110.35

  8. Given: Mean of 96 and σ = 7Find: Find data that shows less that 72% 72% = a z-score of .68 .58 = (D – 96)/ 7 7(.58) = D – 96 4.06 = D – 96 D = 4.06 + 96 D = 100.06

  9. Find the two pieces of data that contain 50% if Mean = 30 and σ = 5 50% of the data is between 25% and 75% (25% above and 25% below) Find z-scores for 25% and 75% z-score for 25% = -.67 z-score for 95% = .67 -.67 = (D – 30) / 5 D = 26.65 .67 = (D – 30) / 5 D = 33.35

  10. Find the two pieces of data that contain 95% if Mean = 40 and σ = 4 95% of the data is between 2.5% and 97.5% (47.5% above and 47.5% below) Find z-scores for 2.5% and 97.5% z-score for 2.5% = -1.96 z-score for 97.5% = 1.96 -1.96 = (D – 40) / 4 D = 32.16 1.96 = (D – 40) / 4 D = 47.84

More Related