Understanding Congruent Chords and Segment Lengths in Circles
240 likes | 376 Vues
This worksheet focuses on concepts of congruent chords, corresponding arcs, and segment lengths in circles. It guides students through problems involving two chords intersecting inside a circle, using flow charts and proofs to establish relationships effectively. Problems cover both chord and secant lengths, ensuring a solid understanding of these fundamental geometric principles.Students will find various exercises, including establishing midpoint calculations, applying the perpendicular bisector theorem, and solving algebraic equations to find segment lengths.
Understanding Congruent Chords and Segment Lengths in Circles
E N D
Presentation Transcript
How do you know when two chords are congruent? • corresponding arcs are congruent B A M P b. equidistant from the center L C LP PM ALP = BMP = 90 D
2x x + 40 2x = x + 40 x = 40
In K, K is the midpoint of RE. If TY = -3x + 56 and US = 4x, find the length of TY. U T x = 8 TY = 32 K E R S Y
IF AC is the perpendicular bisector of segment DB, then… D It’s the DIAMETER!!! Arcs DC and BC are congruent!!! A C B
IN Q, KL LZ. IF CK = 2X + 3 and CZ = 4x, find x. Q x = 1.5 C Z K L
In P, if PM AT, PT = 10, and PM = 8, find AT. P A M MT = 6 T AT = 12
Your turn! ÐUTV ÐXTW. Find WX.___________ 130º 11 Find ___________
Your turn! Find the length of each chord. 96 30 LN = _______ CE = _______
Segment Lengths in Circles • Find the lengths of segments of chords • Find the lengths of segments of tangents and secants
Secant and Tangent 2 Secants intersecet outside Chords intersect inside
Two chords intersect INSIDE the circle Type 1: a ab = cd d c b
Solve for x. 9 6 x x = 3 2
12 2x 8 3x Find the length of DB. x = 4 DB = 20 A D C B
Find the length of each chord. D x = 8 AC = 13 DB = 14 A x - 4 x C 5 10 B
Two secants intersect OUTSIDE the circle Type 2: E A B C D EA•EB = EC•ED
Ex: 3 Solve for x. B 13 A 7 E 4 C x D 7 (7 + 13) = 4 (4 + x) x = 31 140 = 16 + 4x 124 = 4x
Ex: 4 Solve for x. B x A 5 D 8 6 C E 6 (6 + 8) = 5 (5 + x) 84 = 25 + 5x x = 11.8 59 = 5x
Type 2 (with a twist): Secant and Tangent C B E A EA2= EB • EC
Ex: 5 Solve for x. C B x 12 E 24 A (12 + x) 242 = 12 x = 36 576 = 144 + 12x
Ex: 6 5 B E 15 C x A (5 + 15) x2 = 5 x2 = 100 x = 10
Homework Practice Worksheet