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Understanding the Impact of Tides on the Volumetric Flow of the Columbia River

This analysis explores how tidal changes affect the volumetric flow of the Columbia River, applying fluid dynamics principles. Using the formula Q = A * C, where Q is the volumetric flow rate, A is the cross-sectional area, and C is the velocity of the water, we calculate the flow rates based on varying water levels and velocities. For a scenario where the river acts like a half-filled pipe, we derive an area of 234.5 m² with a velocity of 2.25 m/s, resulting in an estimated flow of 527.6 m³/s. This study highlights the fundamental relationships between area, velocity, and flow rate in river dynamics.

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Understanding the Impact of Tides on the Volumetric Flow of the Columbia River

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  1. Moon River How Tides Affect the Volumetric Flow of the Columbia River

  2. Volumetric Flow Q = A*C The volume of fluid = Q Acircle = πr2 C = Velocity of the water

  3. Volumetric FlowThrough a Pipe Plugging in the data… Given: Pipe – 2 m, Velocity = 4m/s Equations: Q = A*C Acircle = πr2 = A = 3 * (2)2. Area = 12 m2 C = Velocity of the water C = 4 m/s Q = (12 m2) * (4 m/s) Q = 48 m3/s

  4. Volumetric FlowThrough a Pipe What would the volumetric flow be if we slowed the water flowing into the pipe, and the pipe was only ½ filled with water? Q = 48 m3/s / 2 Q = 24 m3/s

  5. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = πr2 The river can be thought of as a ½ pipe, so the surface area should be halved.

  6. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.5 m/s Equations: Q = A*C Acircle = πr2 (3)(12.5)2 = 469 m2. Because the river is like a ½ pipe… 469/2 = 234.5 m2.

  7. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = 234.5 m2. C = 2.25 m/s Q = (234.5 m2)(2.25 m/s) Q = 527.6 m3/s

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