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Stoichiometry Problem

Calculate the mass of water formed when 5.87g Mg(OH)2 reacts with 12.84g HCl to produce water and MgCl2. Follow the steps of balancing the equation and determining the limiting reactant.

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Stoichiometry Problem

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  1. Stoichiometry Problem Proceed

  2. Problem: #3 • What mass of water is formed when 5.87 g of Mg(OH)2 reacts with 12.84 g of HCl to form water and MgCl2 Continue.

  3. First Step: Balance the Equation • Mg(OH)2+HCl MgCl2+H20 Mg(OH)2+4HCl 2MgCl2+ 2H20 Mg(OH)2+2HCl MgCl2+2H20 2Mg(OH)2+2HCl 2MgCl2+2H20

  4. WRONG!! Back

  5. SecondStep Starting out with 5.87g of Mg(OH)2, set up the first part of your conversion factor

  6. WRONG!! Back

  7. Third Step After this portion of the equation, what is the next part?

  8. WRONG!! Back

  9. Fourth Step for an answer for your third step, what comes next? After you obtain

  10. WRONG!! Back

  11. Fifth Step: Solution? After multiplying and dividing all of the numbers, what did you obtain in the end? 2.09gHCl 5.28gHCl 3.61gHCl

  12. WRONG!! Back

  13. Sixth Step What is the solution to the problem.. 5.56gH20 6.34gH20 4.92gH20

  14. WRONG!! Back

  15. FINAL STEP • Which is the limiting reactant? 3.61gHCl 6.34gH20

  16. WRONG!! Back

  17. CORRECT!!

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