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working at different rates

Dick can paint a house alone in 10 days, while Jane can complete the task in 6 days. Working together, we want to determine how many days it will take them to paint the house. By calculating their individual rates—Dick paints 1/10 of the house per day and Jane paints 1/6 of the house per day—we can formulate an equation to find the total time needed when cooperating. The approach involves determining the combined rate and solving for the total number of days required to finish painting.

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working at different rates

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  1. working at different rates

  2. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. How many days will it take them to paint the house working together?

  3. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. How many days will it take them to paint the house working together?

  4. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. IN ONE DAY He paints 1/10 of the house and She paints 1/6 of the house

  5. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. IN TWO DAYS He paints 2/10 of the house and She paints 2/6 of the house

  6. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. IN THREE DAYS He paints 3/10 of the house and She paints 3/6 of the house

  7. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. Let x = the number of days it will take them to paint the whole house working together. IN THREE DAYS He paints 3/10 of the house and She paints 3/6 of the house

  8. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. IN x DAYS He paints x /10 of the house and She paints x /6 of the house

  9. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. The fraction of the house that he paints + The fraction of the house that she paints =1 IN x DAYS He paints x /10 of the house and She paints x /6 of the house

  10. Working alone, Dick can paint the house in 10 days. Working alone, Jane can paint the house in 6 days. The fraction of the house that he paints + The fraction of the house that she paints =1 The equation: x/10 + x/6 = 1 IN x DAYS He paints x /10 of the house and She paints x /6 of the house

  11. The equation: x/10 + x/6 = 1

  12. The equation: x/10 + x/6 = 1 After 3 ¾ days the job is finished.

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