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CH3Br, 270110 HBr spectra Agust, heima,... Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxp Agust, www, ...Jan10/PPT-270110ak.ppt. Thus for example:. 152926.9. C + +H 2 +HBr+e -. 150k. C**( 1 D 2 )+H 2 +HBr. 147506.154. 130k. Analyse HBr REMPI in neighbourhood of 75200 cm -1.
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CH3Br, 270110 HBr spectra Agust, heima,... Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxp Agust, www, ...Jan10/PPT-270110ak.ppt
Thus for example: 152926.9 C++H2+HBr+e- 150k C**(1D2)+H2+HBr 147506.154 130k Analyse HBr REMPI in neighbourhood of 75200 cm-1 CH3Br* 75204.554 cm-1 C*(1D2)+H2+HBr 72301.6 70k 2 1 0 J’’ 40k 37602.277 10k CH3Br
Look for H79Br+ and/or H81Br+ ion signals vs 2hv in that region HBr REMPI spectra: 1) See our paper: JCP, 112(24), 10811, (2000): Main reference for HBr (2+1)REMPI is: R. Callaghan & RJ Gordon, JCP, 93(7), 4624, (1990): http://www3.hi.is/~agust/rannsoknir/papers/jcp93-4624-90.pdf
Coefficient values ± one standard deviation a = -4.8333 ± 0.312 b = -1.35 ± 0.144 Dnju cm-1 DJ= 7 5 DJ agust,heima,...Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxp
b = -1.35 ± 0.144 Assuming b =2(B´-B´´) = -1.35 => (B´-B´´) = -0.675 => B´= 8.348244 -0.675 = 7.673244 The deviation from linearity could be due to effect of D´ (?) In which case Dnju =
Coefficient values ± one standard deviation K0 = -3.3488 ± 0.475 K1 = -3.4892 ± 0.479 K2 = 0.87454 ± 0.135 K3 = -0.11082 ± 0.0111
Coefficient values ± one standard deviation K0 = 1.1258 ± 1.08 K1 = -5.5708 ± 0.778 K2 = 1.207 ± 0.168 K3 = -0.11082 ± 0.0111
Coefficient values ± one standard deviation K0 = 8.0145 ± 2.03 K1 = -8.3173 ± 1.14 K2 = 1.5395 ± 0.201 K3 = -0.11082 ± 0.0111
Coefficient values ± one standard deviation K0 = 17.982 ± 3.38 K1 = -11.729 ± 1.58 K2 = 1.872 ± 0.234 K3 = -0.11082 ± 0.0111
It is difficult to simulate the spectrum by using B´and D´parameters for the g state. Hence large perturbation / possibly another spectral system in that region