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7a.

6d. P(1000)=1198(1.0101) 1000 = million people in. 7b. g(x) is a reflection of f(x) over the y-axis. 7a. 7c. g(x)=( ) x = 3 -x = f(-x). 8. g(x)=( ) x is exponential decay. 9. False, all exponential function contain (0,a). True, all y = b x with b 0 or b1 has a

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7a.

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  1. 6d. P(1000)=1198(1.0101)1000 = million people in 7b. g(x) is a reflection of f(x) over the y-axis 7a. 7c. g(x)=()x = 3-x = f(-x) 8. g(x)=()x is exponential decay 9. False, all exponential function contain (0,a) • True, all y = bx with b0 or b1 has a • range y>0 so it is above the x-axis

  2. Section 2.4 #1-11 1. N(3.5)=10(2)3.5 = 113 bacteria 2. 25  4.71 • k(m)=4m & p(x) = 0.6x are exponentials. 4b. 2x = 20 4a. 2x = 20 x 4.32 x 4.3 5b. 102x = 60 5a. 102x = 60 x 2.58 x 2.3 6a. P(1)=1198(1.0101)1 = 1210 million people in 1996 P(2)=1198(1.0101)2 = 1222 million people in 1997 6b. P(n)=1198(1.0101)n 6c. P(10)=1198(1.0101)10 = 1324.6 million people in 2005

  3. 11. If 0<b<1 the graph is strictly decreasing while if b>1 the graph is strictly increasing If 0<b<1 as x gets larger f(x) decreases toward zero, if b>1 as x gets larger f(x) increases without bound If 0<b<1 as x gets smaller f(x) increases without bound, if b>1 as x gets larger f(x) increases without bound Section 2.5 #1-3 1. False f(0) is the initial value • If a>0, 0<b<1 it is an exponential decay model. 3a. In B=37(1.32)x , 37 is the initial value 3b. In B=37(1.32)x , 1.32 is the growth factor

  4. p.110 #15, 16, 18, 19, 20 15a. P(3)=500(1.065)3 = $609.97 b. P(t)=500(1.065)t b. P(n)=2(.9)n 16a. P(1)=2(.9)1 = 1.8 kg P(2)=2(.9)2 = 1.62 kg P(3)=2(.9)3 = 1.458 kg 16c. False, P(6)=2(.9)6  1.06 kg, which is not half of 2 18. Is a function 19. Is a function 20. Is a function

  5. p.117 #11 & p.118 #15, 16, 18, 19, 20 11. P=148.7(1.021)y has a growth factor of 2.1% a. Domain is all reals 15. g(x)=3(1.3)x a. Range is y > 0 16. Asymptote is y=1 18a. Domain is all reals b. Range is y > 0 19a. Domain is [-3,1] b. Range is [-2,0] (-3,0) (1,0) (-1,0) (-1,-2) 20. 2x2 + 5x = 0 x = 0 2x + 5 = 0 2x = -5 x(2x + 5) = 0 x = -5/2

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