1 / 14

CH 6 Mixed Review

CH 6 Mixed Review. CH 6 Mixed Review. 45, 46, 48, 50, 51, & 55. SHOW ME. 45. ANSWER :. 23.0 m/s. GOT IT. v. Velocity after the collision is the horizontal velocity for the projectile. 45. 1.5m. 2.5m. HOR v =. d t. mv + mv = mv. 2.5 .553. v =. 4.52 m/s. v =.

jolene
Télécharger la présentation

CH 6 Mixed Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. CH 6 Mixed Review CH 6 Mixed Review 45, 46, 48, 50, 51, & 55

  2. SHOW ME 45 ANSWER : 23.0 m/s GOT IT

  3. v Velocity after the collision is the horizontal velocity for the projectile 45 1.5m 2.5m HOR v = d t mv + mv = mv 2.5 .553 v = 4.52 m/s v = 22.6 g 5.5g Conservation of momentum Projectile VERT vi = 0 d = 1.5 a = 9.8 t = ? d = vit + 1/2at 2 1.5 = 1/2(9.8)t2 5.5v = (5.5+22.6)(4.52) t = .553 s 5.5v = 127 v = 23.0 m/s

  4. GOT IT SHOW ME 46 ANSWER : 28.7 s

  5. BEFORE AFTER 5 t d t v = .174 = 46 Find the speed the student moves using conservation of momentum mv = mv + mv 0 = 2.6(-5) + 74.5v v = .174 m/s Student will keep sliding at constant speed because there is no friction t = 28.7 s

  6. GOT IT SHOW ME 48 ANSWER : 14.5 m/s north

  7. BEFORE AFTER V? 10m/s 2550 1550 48 5.22 m/s mv + mv = mv 2550v + 1550(-10) = 4100(5.22) 2550v - 15500 = 21402 2550v = 36902 v = 14.5 m/s

  8. GOT IT SHOW ME 50 ANSWER : 14 cm

  9. BEFORE AFTER .7 v? 3.5 .4 .6 .4 .6 d 5 d t v = 2.8 = 50 mv + mv = mv + mv .4(3.5) = .4(-.7) + .6v 1.4 = - .28 + .6v v = 2.8 cm/s There is no friction, so bead continues at constant speed d = 14 cm

  10. GOT IT SHOW ME 51 ANSWER : 339 m/s

  11. 6 cm 8 g 2.5 kg v? BEFORE AFTER 51 Cons of momentum for collision Cons of energy for swing Ebottom = Etop 1/2 mv2 = mgh mv + mv = mv .5v2 = 9.8(.06) .008v = 2.508(1.08) v = 1.08 m/s This is the velocity of the combination immediately after the collision v = 339 m/s

  12. GOT IT SHOW ME 55 ANSWER : .833 m/s 1.17 m/s left

  13. A. F t = mv 55 (2.5)(.5) = 1.5v .833 m/s = v This is the answer since it started at rest B. We know the CHANGE in velocity is .883 …it could be .883 MORE or .883 LESS Since it was moving to the left and the force was to the right, it was slowed down .833 m/s 2.0 - .833 = 1.17 m/s

  14. THE END THE END

More Related