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Understanding Chemical Reactions: Predictions, Classifications, and Balancing

This guide provides a comprehensive overview of predicting products in single and double displacement reactions, along with acid-base interactions and combustion processes. Learn how a more active element can replace a less active one and the importance of solubility tables in determining the occurrence of reactions. Key examples showcase single displacement reactions, double displacement reactions, and neutralization reactions resulting in salt and water. Additionally, the guide offers practical exercises for predicting products and calculating solid product mass from reactants.

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Understanding Chemical Reactions: Predictions, Classifications, and Balancing

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  1. Predicting Products

  2. Single Displacement • Use activity series • A more active element replaces a less active one or the reaction will not occur

  3. NaCl + F2 --->NaF + Cl2NaF + Cl2 --->No reaction

  4. MgCl2 + Na KBr + Cl2FeCl3 + Cu Na2SO4 + Cu 

  5. Double Displacement or Metathesis • Use solubility tables • For a reaction to occur, a ppt must form

  6. BaCl2(aq)+ K2SO4(aq)----->BaSO4(s)+ KCl(aq)

  7. NaCl(aq) + KBr(aq)----->NaBr(aq) + KCl(aq) No Reaction

  8. Name reactants, predict & name products, and balance & classify the reactions on the board

  9. DD or Metathesis • Acid-base: • When an acid is combined with a base, the products will be salt & water

  10. HCl(aq) + NaOH(aq)----->NaCl(aq) + H2O(l)

  11. Mg(OH)2(aq) + H2SO4(aq)MgSO4(aq) + H2O(l)

  12. Ba(OH)2(aq) + CaCl2(aq)ZnCl2(aq) + K2CrO4(aq)KCl(aq) + Na2SO4(aq)

  13. HCl(aq) + NaOH(aq)H2SO4(aq) + KOH(aq)HCl(aq) + NH3(aq)

  14. Combustion • Carbon compound + oxygen yields Carbon dioxide & water

  15. C3H6(g) + O2(g)C4H8O(l) + O2(g) C4H8O4(g) + O2(g)

  16. Predict Products & Balance Rxn • CaCl2 + F2 • CaCl2 + Na  • CaCl2 + KNO3 • CaCl2 + K2SO4

  17. Predict & Balance • AlBr3 + F2 • AlBr3 + Zn  • AlBr3 + Na  • AlBr3 + Ba(NO3)2 • AlBr3 + K2SO4

  18. Calculate the mass of solid product formed when 4.16 g of barium chloride is added to 250 ml of 0.40 M potassium sulfate:

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