1 x 2

Sep 03, 2014

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T’. C’’’. D’’’. B’’’. G’’’. A’’’. T’’’. H’’’. 1 x 3. F’’’. E’’’. 1. Četverostrana uspravna prizma. H”. E”. F”. G”. a) Na kojim se pobočkama može nalaziti točka T ?. T”. Točka T može ležati na pobočki ABFE ili pobočki ADHE. 1 x 2.

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1 x 2

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T’ C’’’ D’’’ B’’’ G’’’ A’’’ T’’’ H’’’ 1x3 F’’’ E’’’ 1. Četverostrana uspravna prizma H” E” F” G” a) Na kojim se pobočkama može nalaziti točka T ? T” Točka T može ležati na pobočki ABFE ili pobočki ADHE. 1x2 b) Neka je nacrt točke T nevidljiv. Odrediti njezinu stranocrtnu projekciju. Da li je vidljiva? A” D” C” B” D’=H’ C’=G’ Nacrt točke T je nevidljiv, ako se ona nalazi na pobočki ADHE. Stranocrtna projekcija te točke je vidljiva. A’=E’ B’=F’

Warm Up 1. 2( w + 1) 2. 3 x ( x 2 – 4)

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Solve log 2 (2 x + 1) – log 2 x = 2

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y 1 y 2 x 1 x 2

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sen 2 x + cos 2 x = 1

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sen 2 x + cos 2 x = 1

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a 1 2 x 2 +

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1 int [][] x={{1},{2,3},{4,5,6}; System.out.print(x[2][2]);

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1 x 2

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f ( x ) = 2 x + 1

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P 1 x V 1 = P 2 x V 2

726 mmHg x 946 mL. P 1 x V 1. =. 154 mL. V 2. A sample of chlorine gas occupies a volume of 946 mL at a pressure of 726 mmHg. What is the pressure of the gas (in mmHg) if the volume is reduced at constant temperature to 154 mL?. P x V = constant. P 1 x V 1 = P 2 x V 2.

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x 1 x 2 x i-1 x i

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y = x 2 -1

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Warm Up Solve each equation. 1. 2 x + 3 = 2 x + 4 2. 2( x + 1) = 2 x + 2

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y 1 y 2 x 1 x 2

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1. Solve x 2 – 2 x – 24 = 0 .

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x cg = (W 1 x 1 + W 2 x 2 + . . .)/ (W 1 + W 2 . . .)

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a  x  b  1 ( x )  y   2 ( x )

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1 x 2

Quick Tables: Random Question Generator To Play: Right click on your mouse and choose the ‘full screen’ option (or View: Play Slide Show). Press the ‘S’ key to start and stop the generator. 1 x 2.

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