1 / 21

Revision: Describe Oxidation-Reduction Processes, 3credits

Revision: Describe Oxidation-Reduction Processes, 3credits. Definitions of Oxidation-Reduction Loss/Gain of electrons Increase/Decrease of oxidation number Determining oxidation numbers. Remember:. A redox reaction is any reaction involving a transfer of electrons .

kitty
Télécharger la présentation

Revision: Describe Oxidation-Reduction Processes, 3credits

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Revision: Describe Oxidation-Reduction Processes, 3credits Definitions of Oxidation-Reduction Loss/Gain of electrons Increase/Decrease of oxidation number Determining oxidation numbers

  2. Remember: • A redox reaction is any reaction involving a transfer of electrons. • In all redox reactions, oxidation and reduction happen at the same time. • Oxidationis loss of electrons/increase in oxidation number. • Reduction is gain of electrons/decrease in oxidation number. • Oxidising agents (oxidants) are themselves reduced. • Reducing agents (reductants) are themselves oxidised.

  3. Rules for oxidation numbers 1. Oxidation number for elements is zero. 0 0 0 0 0 N2, O2, O3, Cu, S8 • Oxidation number of monoatomic ions • is the same as their charge +3 +2 +2 +1 Al3+, Zn2+, Cd2+, Ag+ 3. In polyatomic ions (NO3-), the sum of oxidation numbers equals the charge of the ion. In compounds (HNO3) the sum of the oxidation numbers equals zero.

  4. Rules for oxidation numbers Oxidation number of oxygen in most compounds is –2. Exceptions: H2O2, O22- –1 (peroxides) 5. Oxidation number of hydrogen is +1 Exceptions: bonded to metals LiH 6. Fluorine is always –1. Other halogens are also –1, except when they are bonded to O, then they are positive.

  5. Assign oxidation numbers to all of the elements: Li2O Li = +1 O = -2 PF3 P = +3 F = -1 HNO3 H = +1 +5 O = -2 N = MnO4- Mn = +7 O = -2 Cr2O72- Cr = +6 -2 O =

  6. Revision: Describe Oxidation-Reduction Processes, 3credits Electrochemical cells: Their properties Electrode potentials defined as standard electrode potentials, Eo (unit: Volts, V) Cell diagrams: Use of the symbols “/” (phase boundary) “,” (same phase)and “//” (salt bridge) Half cells Order of notation

  7. Electrochemical definitions • Electrochemical cell: a cell in which oxidation and reduction occur, often in separate compartments • Half cell: a single electrode in an solution containing ions • Electrode: the conductor placed in cells that transfer charge between the external circuit and the electrolyte

  8. Electrochemical definitions • Anode: electrode where oxidation occurs (negative electrode) • Cathode: electrode where reduction occurs (positive electrode) • Electrolyte:substances in the salt bridge (usually liquids) that transfer charge by moving ions • Electrolytic cell: a cell that uses a supply of electricity to bring about a non spontaneous chemical reaction(year 12)

  9. Electrochemical definitions • Electromotive force, EMF, or Eºcell: the potential difference across a voltage source when no current is following • Standard reduction (electrode) potential Eºstandard electrode potential measured in volts under standard conditions (25oC, 1molL-1, 1 atm), which indicates the ability of a species to gain electrons

  10. The salt bridge allows the movement of ions between the two half cells so that charges can be balanced. It completes the electric circuit. Writing cell diagrams:Start on the left (oxidation)Zn/Zn2+//Cu2+/CuTake care when the electrode is not taking part in the reactionsTake care that you separate phases with the symbol /Take care that species in the same phase are separated by a comma If the voltmeter (that restricts the current flowing) is replaced by a wire, the reactions will take place more quickly. Here the copper electrode would gain mass, the zinc electrode would loose mass. http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/galvan5.swf

  11. Pt/H2/H+// Give the half cell diagram

  12. Revision: Describe Oxidation-Reduction Processes, 3credits Electrochemical cells: Calculations related to Electrochemistry Spontaneity of oxidation-reduction reactions Applications involving electrochemical cells (details of particular cells, eg dry cells, will be provided as required)

  13. Calculating emf The emf of an electrochemical cell is calculated using the following formula: Eocell= Eo(RHE) – Eo(LHE) note: do not change the sign of the standard potentials If the emf is positive: The electron flow is from left to right and the oxidation takes place in the left half cell. If the emf is negative: The electron flow is from right to left and the oxidation takes place in the right half cell.

  14. Calculating emf greater Eo: Strongest Oxidant, Reduction reaction • lower Eo: Strongest Reductant, Oxidation reaction

  15. Predicting reactions To predict whether reactions happen spontaneously, the emf is calculated. Fe2+/Fe3+ = 0.77 Zn2+ /Zn = - 0.76 Does Zn react with Fe3+? Zn is the possible loser of electrons Zn/Zn2+//Fe3+, Fe2+/C Eocell= 0.77 – (- 0.76) = 1.53 V The emf is positive, therefore the electron flow is from left to right and oxidation takes place in the left half cell. That means that Zn reacts spontaneously with Fe3+. Does Zn2+ react with Fe2+? Fe2+ is the possible loser of electrons C/ Fe2+, Fe3+ //Zn2+/Zn Eocell= - 0.76 -0.77 = -1.53 V The emf is negative, therefore the electron flow is from right to left and oxidation takes place in the right half cell. That means that Zn2+ does not react spontaneously with Fe2+.

  16. The Lead Acid Cell - a rechargeable battery 2PbSO4 + 2H2O Pb + PbO2 + 2H2SO4 When the battery is charged, lead (II) ions (Pb2+) in lead sulfate are reduced to Pband oxidised to lead (IV) ions (Pb4+) in lead oxide. Observation: A build up of lead at the anode and a build up of PbO2 at the cathode. When the battery is discharged (providing energy to the car), the reaction is reversed and PbSO4 is produced. This will build up on cathode and anode. If any PbSO4 falls off the plate (which happens after long use), then it can not react and the battery needs replacing.

  17. The Dry Cell - Lechlanche cell You do not need to know the details about the Dry Cell as there are different types and in the exam a different example may be chosen. A dry cell is very compact, so it may be difficult to identify cathode, anode and the half cell reactions. The electrolyte used is a paste made up of alkaline or acidic salts. For the Lechlanche cell above identify: Cathode: Anode: Oxidation: Reduction: Exam Questions: They may involve discussing the suitability of a redox pair for the construction of a dry cell. The production of a gas indicates no suitability! graphite Zinc case Zn to Zn2+ Mn4+ to Mn3+

  18. Revision: Describe Oxidation-Reduction Processes, 3credits Redox reactions: Appearance and state of common oxidants and reductants Calculations involving mole ratios (titrations)→go through examples in your book

  19. In previous exam papers, students struggled to achieve because: they did not read the question properly they were not able to show the direction of electron flow could not assign oxidation numbers did not give V as the unit for Eocell, or used the wrong sign could not write standard cell diagrams, forgot inert electrodes did not know that a salt bridge completes the circuit, allows ion flow did not know what happens when the voltmeter is replaced by a wire used the term “dissolve” incorrectly when referring to the decrease of mass of an electrode could not identify the oxidised and reduced form did not know the colours of species did not identify strongest reductant/oxidant (quoted incorrectly a redox pair)

More Related