Calculating Distance Covered by a Train Coming to Rest

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A train traveling at a constant velocity of 25 m/s comes to a stop after applying the brakes. The brakes induce a uniform deceleration of 5 m/s². To find the distance the train covers while coming to rest, we use the kinematic equation ( v^2 = u^2 + 2as ). Here, the initial velocity (u) is 25 m/s, the final velocity (v) is 0 m/s, and the acceleration (a) is -5 m/s². Solving for distance (s) gives us a total of 62.5 meters covered before the train stops.

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May 18, 2026

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Calculating Distance Covered by a Train Coming to Rest

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Example A train travelling with constnat velocity of 25 m/s comes to rest, after applying the brakes. Give that the brakes produced a cantant deceleration of 5 ms-2, calculate the distance covered bty the train in coming to rest. Solution (a) Given data: u = 24, v = 0, a = -5 need: s v2 = u2 + 2as Required equation: 0 = 242 – 2 x 5 x s Give s = 57.6 m.