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Use mesh-current method to find power dissipated in 1Ω resistor. Identify mesh currents I3, I2, I1 and solve equations to get I1=7A, I2=6A, I3=5A, calculate power P1Ω=36W.
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Assessment Problem # 4.12 Mesh-Current Method Special Case Current Source in a branch ECE 201 Circuit Theory I
Use the mesh-current method to find the power dissipated in the 1 Ω resistor. ECE 201 Circuit Theory I
Identify the mesh currents I3 I2 I1 ECE 201 Circuit Theory I
Assign the voltage polaritiesIdentify the voltage @ the 2A source + - I3 - + + - + - V - + I2 I1 + - - + ECE 201 Circuit Theory I
Write the mesh-current equations (1) + - I3 - + + - + - V - + I2 I1 + - V + 2I1 – 2I2 = 10 - + ECE 201 Circuit Theory I
Write the mesh-current equations (2) + - I3 - + + - + - V - + I2 I1 + - -2I1 +5I2 -2I3 = 6 V + 2I1 – 2I2 = 10 - + ECE 201 Circuit Theory I
Write the mesh-current equations (3) + - I3 -V -2I2 +4I3 = 0 - + + - + - V - + I2 I1 + - -2I1 +5I2 -2I3 = 6 V + 2I1 – 2I2 = 10 - + ECE 201 Circuit Theory I
Eliminate V from the equations for meshes 1 and 3 ECE 201 Circuit Theory I
Write the equations in matrix form Solving with a TI-89, [6,-4;-4,5],[18;2])ENTER ECE 201 Circuit Theory I
Solving • Result looks like I1 = 7A I2 = 6A Calculate I3 I3 =I1 – 2 = 5A ECE 201 Circuit Theory I
Find the power dissipated in the 1Ω resistor • P1Ω = (I2)2R = (6)2(1) = 36 W ECE 201 Circuit Theory I