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Stellar Evolution: Parts of Chapters 12,13,15,16

Learn about the different stages of stellar evolution, from the formation of stars in dark nebulae to their time on the main sequence. Discover the conditions for a cloud to collapse and form a star, as well as the lifespan of stars on the main sequence.

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Stellar Evolution: Parts of Chapters 12,13,15,16

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  1. Stellar Evolution: Parts of Chapters 12,13,15,16 Stars lose energy - hence they must evolve. There are different time scales on which stars (Sun) evolve: (1) Nuclear time scale tnuclear = (0.007 x 0.1 x Mc2)/L ~ 1010 yr (2) Thermal time scale tthermal = (0.5GM2/R)/L ~ 2 x 107 yr (3) Dynamical time scale tdynamical = remove pressure - free fall time from surface to centre = (2R3/GM)1/2 ~ 0.6 hour!

  2. Stellar Evolution (Formation) • Begins in clouds of gas and dust called dark nebulae. • Dark nebulae are observable since they block light from background stars. • They have masses 20 - few 1000 Msun and sizes 1 pc - 100 pc. • Earlier stages of star formation exist as Giant Molecular Clouds • Detected at radio wavelengths • 103 - 106 solar masses; sizes of 20 pc - 100 pc; and T ~ 10K • Molecular emission of CO often detected at  = 2.6 mm Star Formation

  3. 1028 Stellar Evolution (Formation)

  4. Stellar Evolution (Formation) Under what conditions will a cloud collapse to form a star? Jeans (Sir James - 1902) Instability Criterion. • Assume a spherical cloud:       radius Rc, uniform c, total mass Mc = 4/3  cRc3,speed sound cs. • Compress region slightly. It takes time, tsound = Rc/cs, for sound waves to cross region and attempt to re-establish pressure balance. • At same time, gravity tries to contract system and does so on free-fall time tff = 1/(G)1/2. • If sound crossing time is less than tff, (tsound<tff), pressure wins and system bounces back to stable equilibrium, otherwise gravity wins. • Thus, criterion for gravitational collapse is tff < tsound. • With some algebra we derive MJ = c3s/(G3/21/2), with cs = (P/)1/2 and P = kT/mH we get MJ = (kT/mHG)3/2 x 1/1/2

  5. Stellar Evolution (Formation) Example: in the dense core of a typical giant molecular cloud: T~ 10 K;  ~ 3 x 10-17 kg/m3;  ~ 2 for pure H2 gas (X= 1, Y = Z = 0) Thus MJ ~ 2 Msun The characteristic mass of these dense cores is ~ 10 Msun so they are unstable to gravitational collapse - consistent with them being sites of star formation. Collapse could also be triggered by external pressure on cloud from, for example, a shock wave from nearby supernova explosion. MJ = (kT/mHG)3/2 x 1/1/2

  6. Eventually, the star’s core is hot enough for nuclear reactions. Star reaches hydrostatic equilibrium, on main sequence. Stellar Evolution (Formation) • In the collapsing cloud, energy is released by gravitational contraction. The star shrinks and begins to heat up. • Initially, radiation passes right through star so that Teff stays nearly constant. Therefore, as R drops so does L (L = 4R2Teff4 ). • Contraction is originally on the dynamical timescale. Eventually density increases and so does opacity. A larger fraction of energy is transformed into heat. Pressure increases, raising the resistance to the collapse so the contraction slows. Teff rises with little change in R. Therefore, star moves to higher L. Similar to Fig 11.1

  7. For first few x 104 years, the star contracts from the interstellar medium and radiates away gravitational energy. • By 106 years, the first nuclear reactions involving light elements start: eg p+ + 2H 3He +  Stellar Evolution (Pre Main Seq.) • 2H (from Big Bang) has very low abundance so the energy released from this reaction just slows the contraction rate a bit. • Other reactions: 6Li + p+ 3He + 4He 7Li + p+  2 4He 11B + p+  3 4He • All abundances are low, so the contraction rate is minimally affected.

  8. Stellar Evolution (Pre Main Seq.)

  9. Young Stars and Planet Formation

  10. Stellar Evolution (Main Sequence) • Life on Main Sequence (§ 13.1) - • Core H burning and hydrostatic equilibrium is the longest lived stage in a star’s life. HOW LONG DOES IT LAST? • Mass - Luminosity relation L  M3.5 • Energy produced by fusion E = Mc2 M = mass destroyed = 0.007 x mass H fused Mass of H available to fuse  total mass star (0.1 based on models) Thus M  M  E M or E  M • During main sequence stage, L ~ constant, thus L = energy from fusion / MS lifetime = E/tms or tms = E/L = M/M3.5 tms = M-2.5 • Thus,massive stars have shorter main sequence lifetimes than small mass stars. • In terms of Sun’s lifetime: tms/tmssun = (M/Msun)-2.5

  11. Stellar Evolution (Main Sequence) • Low mass stars live for very long times • High mass stars are short-lived

  12. Stellar Evolution (Star Clusters) Star clusters are: • Coeval (all stars same age) • Same metal abundance (formed from same gas cloud) • Have a range in masses in them (mass function)

  13. Observed H-R Diagram compared to theoretical isochrones - all stars with same age Stellar Evolution (Star Clusters) • Many stars can condense from the same giant molecular cloud  star cluster. • Massive stars reach main sequence first and evolve from it earlier also (tms  M-2.5) • As time advances, high mass tip of main sequence shortens and evolved stars appear in upper right of H-R Diagram • Position of main sequence turnoff  age of cluster Evolved stars young old Synthetic Clusters Different Age

  14. 5 x 106 yr 107 yr 3 x 107 yr 108 yr Synthetic Clusters Stellar Evolution (Star Clusters) youngest oldest Real Clusters

  15. Stellar Evolution (Star Clusters)

  16. Stellar Evolution (Death of the Sun) How will the Sun die? • Sun has enough H in its core to produce energy for about 1010 yrs. (It is about halfway through its life now.) • When the core’s H is exhausted, there will be no more nuclear energy to heat the gas. Gravity will win over gas pressure and the core will collapse. • Gravitational potential energy of the core will be converted to heat as it shrinks. • This new heat source will trigger new fusion reactions: (3-) He + He + He  C and C + He  O • Outer layers of the Sun will expand because of extra heat RED GIANT • Eventually, the surface gas will have enough kinetic energy to escape core’s gravity ( to form a planetary nebula), leaving behind a “naked core” of C and O  WHITE DWARF.

  17. Stellar Evolution (Death of the Sun) Planetary nebulae

  18. Stellar Evolution (Death of the Sun) • When nuclear fuel is exhausted, the core will contract again. Low mass stars never get hot enough for nuclear reactions beyond formation C, O. • Core will shrink and electrons in core will be forced together. • Effects of Uncertainty Principle come into play when matter is compressed xp ~ h- so there is zero-point energy (even at T = 0 K) Edeg = p2/2m = h-2/2m(x)2 which increases as size decreases Pdeg = Edeg/V • So for N particles in volume V, where particle density n = N/V, x = (V/N)1/3 • Hence Pdeg = N/V(p2/2m) = N/V(h-2/2m) (N/V)2/3 = (h-2/2m)n5/3 so Pdeg  5/3

  19. Stellar Evolution (Death of the Sun) • The pressure of the degenerate electrons can provide a pressure force even at 0 K. • Pdeg5/3 (independent of T). NB Pdeg not  T - perfect gas law breaks down. • Recall that P  M2/R4 and  M/R3. With P 5/3 weget: M2/R4 (M/R3)5/3  R  M-1/3 or M  1/V (Note how counter-intuitive this relation is). White Dwarfs •  ~ 106 g/cm3; 105 K > T > 3000 K • Radiate away stored heat. Slowly approach 0 K. • If M > 1.4Msun, gravity will exceed the pressure of the degenerate electrons and the white dwarf will collapse.

  20. Stellar Evolution (Death Massive Star) • Gravity strong enough to squeeze C-O core until T rises high enough to fuse C. • C  Ne, Mg and O, and briefly stabilizes star until C used up. • Again, core collapses. Egrav turned into more heat  core hot enough fuse Ne. • Ne  O, Mg and cycle repeats with O  Si, S, Ph then Si  Fe then Fe  ?? • Fe most strongly bound nucleus. Its formation consumes energy. By this time,  > 109 g/cm3, T > 3 x 109 K. • Now get 56Fe +  13 4He + 4n - what kind of nuclear reaction is this? ( here ~ 100 Mev and further drains thermal energy of core). • Star collapses rapidly, T continues to rise, star almost in free-fall 4He  2p + 2n eventually p + e-  n +  • Two possible outcomes - n degeneracy stops collapse (neutron star) or complete gravitational collapse (black hole).

  21. Stellar Evolution (Death Massive Star) The final 1.4 second: • Sudden core collapse. T soars to > 5 x 109 K,  reaches 4 x 1014 g/cm3 (thimble = mass of a mountain!), intense flood of neutrinos emitted. • Pressure forces electrons to combine with protons to make neutrons - core composed entirely of neutrons. • Superdense matter in core stops contracting abruptly - but layers above still plunging inward at 10-15% speed of light. This material hits core and “bounces”. • Shock wave rebounds throughout star, ripping away outer envelope and most of star’s mass ejected (>90%). SUPERNOVA • In next second a SN can release as much energy (mostly neutrinos) as Sun does in 1010 years.

  22. Supernovae

  23. Radio pulsar period 0.714 s • Distribution of periods Neutron Stars / Pulsars • Masses ~ 1.4 Msun - presence made known as PULSARS • Size ~ 10 km Model of pulsar

  24. Black Holes • Escape velocity > speed light Vesc = (2GM/R)1/2 > c  R < 2GM/c2. • R is called Schwarzschild Radius and defines the event horizon. • For example with M = 10 Msun R < 30 km. • For Earth to be a black hole R < 1 cm! • Presence of black holes is suggested in binary systems - high mass dark component and x-ray source.

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