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Higher Derivatives

2.3 Geometrical Application of Calculus. Higher Derivatives. Just Differentiate again. and again. and again. 2.3 Geometrical Application of Calculus. 1. Find the first 4 derivatives of. f(x) = x 3 - 4x 2 + 3x -2. f’(x) = 3x 2 - 8x +3. f’’(x) = 6x - 8. f’’’(x) = 6. f’’’’(x) = 0.

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Higher Derivatives

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  1. 2.3 Geometrical Application of Calculus Higher Derivatives Just Differentiate again and again and again.

  2. 2.3 Geometrical Application of Calculus 1. Find the first 4 derivatives of f(x) = x3 - 4x2 + 3x -2 f’(x) = 3x2 - 8x+3 f’’(x) = 6x - 8 f’’’(x) = 6 f’’’’(x) = 0

  3. 2.3 Geometrical Application of Calculus Rules for Differentiation If f(x) = xnthen … f’(x) = nxn-1 and If f(x) = axnthen … f’(x) = anxn-1

  4. 2.3 Geometrical Application of Calculus Rules for Differentiation Function of a Function Rule If y = (u)nthen … or

  5. 2.3 Geometrical Application of Calculus Rules for Differentiation Product Rule If y = uvthen …

  6. 2.3 Geometrical Application of Calculus Rules for Differentiation Quotient Rule If y = uthen … v

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