1 / 7

Understanding Parallel RLC Circuit Representations and Power Calculations

This guide explores the behavior of a parallel RLC circuit, focusing on phasor representation and the relationship between voltage and current. It explains the roles of resistance (Rt), inductive reactance (XL), and capacitive reactance (XC) in phase relationships, showcasing how the total current can be expressed using polar form. We discuss the calculation of impedance (Zt) using the formula Zt = E/It, along with power calculations such as total power (Pt), reactive power (QT), and apparent power (St). Power triangles are also illustrated to enhance understanding.

Télécharger la présentation

Understanding Parallel RLC Circuit Representations and Power Calculations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Parallel RLC

  2. Circuit Representation

  3. Resistance Rt @ 0 degrees as I is in phase Inductive Reactance XL @ -90 degrees I lags Capacitvie Reactance Xc @ 90 degrees I leads Current Total Formula by use of polar form It = Ir<0 + Ixl<-90 + Ixc<90 It = __ @angle which is the p.f< of the ckt Current In Parallel RLC

  4. Phasor Representation

  5. Impedance Triangle Cannot be used!! Impedance is only calculate by this formula Zt = E / It Impedance

  6. P.F is found through current calculations Power Total Pt = Pr or Pt = E x Ir x P.F Reacitive Power ( calculate same as series) QXL = E x IXL QXC = E x Ixc Qt = QXL - Qxc Qt=√S²-P² Apparent Power St = Pt@0 + Qt@90 or -90 St= Es x It St - __@ angle – p.f angle same as current angle Power Triangle

  7. Power Triangle

More Related