1 / 6

Stoichiometry & Percent Yield Practice 2 Al + 6 HCl  2 AlCl 3 + 3 H 2

Solution:. Stoichiometry & Percent Yield Practice 2 Al + 6 HCl  2 AlCl 3 + 3 H 2. Calculate theoretical yield:. 95 g of hydrochloric acid are reacted with excess aluminum producing 2.2 g of hydrogen gas. What is the percent yield?. Next, calculate % yield:. Solution:.

obelia
Télécharger la présentation

Stoichiometry & Percent Yield Practice 2 Al + 6 HCl  2 AlCl 3 + 3 H 2

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Solution: Stoichiometry & Percent Yield Practice2 Al + 6 HCl  2 AlCl3 + 3 H2 Calculate theoretical yield: 95 g of hydrochloric acid are reacted with excess aluminum producing 2.2 g of hydrogen gas. What is the percent yield? Next, calculate % yield:

  2. Solution: Stoichiometry & Percent Yield Practice2 HgO  2 Hg + O2 Begin like you are calculating the theoretical yield: 42 g of mercury(II) oxide are decomposed. If the % yield is 99.0%, what mass of oxygen gas will actually be produced? Then, multiply by the % yield:

  3. Solution: Stoichiometry & Percent Yield Practice2 Na2O2 + 2 H2O  4 NaOH + O2 Begin by changing the actual yield into a theoretical yield by dividing by the % yield: What mass of sodium peroxide is needed to produce 19 g of oxygen gas if the % yield is 96.0%? Then, do a typical stoichiometric calculation:

  4. Solution: Stoichiometry & Percent Yield Practice4 Al + 3 O2 2 Al2O3 Calculate theoretical yield: 16 g of aluminum are reacted with excess oxygen gas producing 29 g of aluminum oxide. What is the percent yield? Next, calculate % yield:

  5. Solution: Stoichiometry & Percent Yield PracticeFeCl3 + 3 NH4OH  3 NH4Cl + Fe(OH)3 Begin like you are calculating the theoretical yield: 13 g of iron(III) chloride are reacted with excess ammonium hydroxide. If the % yield is 95.5%, what mass of ammonium chloride will actually be produced? Then, multiply by the % yield:

  6. Solution: Stoichiometry & Percent Yield Practice2 Na + Cl2 2 NaCl Begin by changing the actual yield into a theoretical yield by dividing by the % yield: What mass of chlorine is needed to produce 22 g of sodium chloride if the % yield is 97.0%? Then, do a typical stoichiometric calculation:

More Related