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PAPER 2

WORK SHOP TECHNIQUE TO ANSWER PRA SPM (JPNWPKL). PHYSICS PAPER 2. PAPER 2 . 4531/2. SECTION A. 22 SEPTEMBER 2011. PN ZALIPAH MASKURI (SMSASKL). PAPER 2(Section A) 8 Structure Question(Q1 – Q8). 1 hour and 30 minutes. Total Marks for Paper 2 Section A (60 Marks). P.

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PAPER 2

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  1. WORK SHOP TECHNIQUE TO ANSWER PRA SPM (JPNWPKL) PHYSICS PAPER 2 PAPER 2 4531/2 SECTION A 22 SEPTEMBER 2011 PN ZALIPAH MASKURI (SMSASKL) ZMSMSASKL

  2. PAPER 2(Section A) 8 Structure Question(Q1 – Q8) 1 hour and 30 minutes Total Marks for Paper 2 Section A (60 Marks)

  3. P Question 1(Knowledge, understanding & application) 1 Diagram 1 shows a micrometer screw gauge when the jaws are closed. a) Name the part label P b) What is the function of the part label P? P Rachet 1 mark To ensure the pressure exerted does not exceed // undue pressure is not exerted 1 mark

  4. Question 1(Knowledge, understanding & application) • What is the value of zero error shown by the micrometer above? • Give one reason why micrometer screw gauge is more accurate compare to a vernier calliper -0.02 mm 1 mark The scale is smaller 1 mark

  5. Question 2(Knowledge, understanding & application) Diagram 2 shows a boy throwing a ball upwards at a velocity of 10 m s-1. The ball decelerates to a maximum height before accelerating downwards. Diagram 2

  6. Question 2(Knowledge, understanding & application) c) Sketch a displacement, s against time,t graph to describe the motion of the ball. 2 marks

  7. Question 3(Knowledge, understanding & application) Diagram 3 shows an arrangement of apparatus used to determine the atmospheric pressure in a laboratory. The length of the glass tube is 100 cm and the atmospheric pressure in the lab is 75 cm Hg.

  8. Question 3(Knowledge, understanding & application) Mercury Barometer 1 mark • Name the apparatus shown in Diagram 3. • What is in space X • (i) What is the value of H? (ii) What happens to height, H, when this apparatus is submerged in water. (d ) The number of the coil increases the strength of the magnetic field increases. . Vacuum 1 mark 75 cm/0.75 m/750 mm 1 mark Increase 1 mark

  9. Question 3(Knowledge, understanding & application) (iii) Give a reason for your answer in c(ii). (d)State one application of atmospheric pressure in everyday life. The pressure outside glass tube increases // pressure of water + atmospheric pressure 1 mark Vacuum cleaner// siphon // straw // syringe // water pump 1 mark

  10. Question 4(Knowledge, understanding & application) Diagram 4 shows a truck pulling a car with a cable. The cable is at an angle of 600 to the horizontal. The force, F, of the cable is 1500 N. Diagram 4

  11. Question 4 (Knowledge, understanding & application) Anything that can move a stationary object // stop a moving object // change direction / shape / speed of an object. 1 mark (a )What is meant by force? .

  12. Question 4(Knowledge, understanding & application) (b) On Diagram 4, draw the horizontal component, Fx and the vertical component Fy for F. In your drawing show the direction of Fxand Fy. 2 mark

  13. Fx = 1500 x cos 60 = 750 N Question 4(Knowledge, understanding & application) (c) Calculate the magnitude of the horizontal component, Fx. (d) (i) What is the effect of the component of forces, Fxand Fy to the towed car? Fx = 1500 x cos 60° = 750 N 1 mark Fx : to make car move forward // overcome frictional force 1 mark Fy: to lift the car off the ground // to move the car upwards// to overcome the weight of the car 1 mark

  14. Question 5 (KUA and Conceptualization Skill) (a )Diagram 5.1 and Diagram 5.2 show the hair shampoo is pressed out with the same force from a shampoo container. .

  15. Question 5 (KUA and Conceptualization Skill) Normal Force / surface area // Normal force per unit area 1 mark (a)What is meant by pressure ? (b) Based on Diagram 5.1 and Diagram 5.2, compare (i) the volume of shampoo in the container . Diagram 5.2 is bigger than Diagram 5.1/ greater // vice versa 1 mark

  16. Question 5 (KUA and Conceptualization Skill) (b) Based on Diagram 5.1 and Diagram 5.2, compare (ii) the volume of shampoo that spurts out from the container (c ) Based on your answer in (b), (i) relate the volume of shampoo in the container with the volume of shampoo that spurts out from the container. . Diagram 5.2 is bigger than Diagram 5.1 / greater// vice versa 1 mark When the volume of shampoo in the container is less, the volume of shampoo spurted out from the container is less // vice versa 1 mark

  17. Question 5 (KUA and Conceptualization Skill) (c ) Based on your answer in (b), (ii) relate the volume of shampoo that spurts out from the container with the pressure exerted by the shampoo. (1 mark) (iii) state the relationship between pressure and the volume of shampoo in the container. When the volume of shampoo spurted out from the container is big, the pressure exerted towards the shampoo is big // vice versa When the volume of the shampoo in the container increase the pressure also increases. 1 mark

  18. Question 5 (KUA and Conceptualization Skill) Liquid used is non compressible / hard to compress 1 mark (d) State one characteristic of the liquid (e) Name the principle involved that enable the shampoo to spurt out from the container. Pascal’s principle 1 mark

  19. Question 6 (KUA and Conceptualization Skill) Diagram 6.1 and 6.2 show a virtual image produced by a plane mirror and a convex mirror respectively. . Diagram 6.1 Diagram 6.2

  20. Question 6 (KUA and Conceptualization Skill) Image that cannot be formed on screen 1 mark (a) What is meant by virtual image? (b) Based on Diagram 6.1 and Diagram 6.2, (i) compare the size of the image . Image in Diagram 6.1 is bigger than Diagram 6.2// vice versa 1 mark

  21. Question 6 (KUA and Conceptualization Skill) (b)(ii) state one other similarity of the image formed besides virtual. Upright 1 mark

  22. Question 6 (KUA and Conceptualization Skill) (c )InDiagram 6.3, draw a ray diagram to show how the image in Diagram 6.2 is formed. DIAGRAM 6.3

  23. Question 6 (KUA and Conceptualization Skill) (e) Name the light phenomenon that occurs. (f) State one advantage of using convex mirror as the side mirror of a car. . Reflection 1 mark Wide angle of reflection // wider the vision 1 mark

  24. Question 7 (KUA and Problem Solving) Diagram 7 shows a hydrometer used to determine the density of a liquid. Diagram 7

  25. Question 7 (KUA and Problem Solving) Archimedes’s principle // Forces in equilibrium // Principle of flotation (a) (i) Name the physics principle involved . 1 mark (ii) Explain why the hydrometer floats on the surface of the liquid. . The buoyant force = weight of the hydrometer // density of liquid > density of hydrometer // the volume of the liquid displaced by the hydrometer is large

  26. Question 7 (KUA and Problem Solving) (a)(iii) The volume of the hydrometer under the surface of the liquid is 25 cm3. The density of liquid • measured is 0.8 g cm-3. Calculate the buoyant force exerted to the hydrometer. [ 2 marks ] (b)(i)he hydrometer in Diagram7 is unsuitable to measure the density of an acid solution which has smaller density. [ 2 marks ] . F =  V g = (8 x 102) x ( 25 x 10- 6 ) x 10 // = 0.2 N the plastic wall is replaced by a glass wall increase the volume of the air filled bulb // reduce the mass of lead shot

  27. Question 7 (KUA and Problem Solving) to avoid corrosion 1 mark (b) (ii) Give the reasons for your answer in b(i) (iii) Suggest one method to increase the stability of the hydrometer (c ) What happens to the hydrometer in Diagram 7 when it is placed in a higher density liquid? . to increase the buoyant force // to float the hydrometer 1 mark add more lead shot 1 mark Less submerged //hydrometer floats higher 1 mark

  28. Question 8 (KUA and Decision Making) Diagram 8.1 and Diagram 8.2 show a block of iron and a block of aluminium, each of mass 250 g, are heated by an immersion heater. The power of the immersion heater is 50 W. . Diagram 8.1 Diagram 8.2

  29. Question 8 (KUA and Decision Making) The temperature-time graph for the two experiments are shown in diagram 8.3 . Diagram 8.3

  30. Question 8 (KUA and Decision Making) Energy transfer from higher temperature body to lower temperature // type of energy that flow 1 mark (a) What is meant by heat? • Based on Diagram 8.3, calculate the change in temperature per minute for; (i) Iron . 80 2 = 40 °C per minute 1 mark 1 mark

  31. Question 8 (KUA and Decision Making) • Based on Diagram 8.3, calculate the change in temperature per minute for; (ii) Aluminium . 100 -20 7 = 80 7 = 11.43 °C per minute 1 mark 1 mark

  32. Question 8 (KUA and Decision Making) Iron 1 mark (c) Based on your calculation, which metal gets hot faster? Explain your answer. (d) Determine the specific heat capacity for iron and aluminium. . the rate of change of temperature is higher 1 mark C iron = 50 x 2 x 60 0.25 x 80 = 300 J kg-1 °C -1 2 mark C Al = 50 x 8 x 60 0.25 x 80 = 1200 J kg-1 °C -1 1 mark

  33. Question 8 (KUA and Decision Making) (e) Table 8 shows the specific heat capacity of materials which could be used to make a frying pan. • Material Based on your answer in (c) and (d) , which material would be suitable to make a frying pan? Explain your answer. .

  34. Question 8 (KUA and Decision Making) Based on your answer in (c) and (d) , which material would be suitable to make a frying pan? Explain your answer. A 1 mark it has lowest specific heat capacity // easily to get hot 1 mark

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