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Gas laws describe the behavior of gases under various conditions of pressure, volume, and temperature. Gases expand to fill their containers and lack a definite shape or volume. Key principles include Boyle's Law, which states that increasing pressure at constant temperature decreases volume, and Charles's Law, which indicates that increasing temperature at constant pressure increases volume. Pressure is calculated using the formula P = Force/Area, measured in pascals. This guide provides essential calculations, examples, and explanations of gas behavior under different scenarios.
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A gas particle spreads apart, filling all the space available. A gas does not have a definite shape of volume.
When working with gases there is a relationship between the gas’s:* volume* temperature* pressure.
Pressure = is due to the collision of gas particles with one another and the walls of the container.
Calculating Pressure P = Force / AreaPressure (P) is measured in Pascals (Pa) or kilo- Pascals (kPa).Force (F) is measured in Newtons (N).Area (A) is measured in m2.P = Force / Area
Calculating Pressure PracticeA machine applies a force of 252 N on a piston having an area of 0.430 m2. Calculate the pressure.
A trash compactor exerts a force of 5,600 N over an area of 0.342 m2. Calculate the pressure in kPa. You will need to divide the pressure by 1000 to convert to kPa.
Boyle’s Law (Pressure)- When the pressure of a gas at constant temperature is increased, the volume of the gas decreases. When pressure is decreased the volume increases. Pressure = Volume
Charlie’s Law: (Temperature)- When the temperature of a gas is increased at constant pressure, its volume increases. Temperature = Volume- When the temperature of a gas decreases at constant pressure the volume decreases.Temperature = Volume
P1V1 = P2V2 T1 T2Temperature is measured in K°(Kelvin). 273° K = 0° C = 32° F
The pressure of a gas remains constant at 10 Pa and the temperature changes from 273°K to 283°K. The volume starts at 20 L. What is the volume after this temperature increase?
P1V1= P2V2 T1 T2 (10 Pa) (20 L) = (10 Pa) (? L) 273°K 283°K 0.732 = 0.0353 (?L) 0.732 /0.0353 = (?L) V2 = 20.7 L
The temperature of a gas remains constant at 300 °K and the pressure changes from 5 Pa to 10 Pa. The volume starts at 20 L. What is the volume after this pressure increase?
P1V1= P2V2 T1 T2 (5 Pa)(20 L) = (10 Pa)(? L) 300°K 300°K 0.333 = 0.0333 (?L) 0.333/0.0333 = 10 L