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Topic: Gas Laws

Topic: Gas Laws. A gas particle spreads apart, filling all the space available. A gas does not have a definite shape of volume. When working with gases there is a relationship between the gas’s: * volume * temperature * pressure.

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Topic: Gas Laws

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  1. Topic: Gas Laws

  2. A gas particle spreads apart, filling all the space available. A gas does not have a definite shape of volume.

  3. When working with gases there is a relationship between the gas’s:* volume* temperature* pressure.

  4. Pressure = is due to the collision of gas particles with one another and the walls of the container.

  5. Calculating Pressure P = Force / AreaPressure (P) is measured in Pascals (Pa) or kilo- Pascals (kPa).Force (F) is measured in Newtons (N).Area (A) is measured in m2.P = Force / Area

  6. Calculating Pressure PracticeA machine applies a force of 252 N on a piston having an area of 0.430 m2. Calculate the pressure.

  7. P = F / AP= 252 N/ 0.430 m2P= 586 Pa

  8. A trash compactor exerts a force of 5,600 N over an area of 0.342 m2. Calculate the pressure in kPa. You will need to divide the pressure by 1000 to convert to kPa.

  9. P= F / AP= 5,600 N / 0.342 m2P= 16374.37 /1000 = 16.37 kPa

  10. Boyle’s Law (Pressure)- When the pressure of a gas at constant temperature is increased, the volume of the gas decreases. When pressure is decreased the volume increases. Pressure = Volume

  11. Charlie’s Law: (Temperature)- When the temperature of a gas is increased at constant pressure, its volume increases. Temperature = Volume- When the temperature of a gas decreases at constant pressure the volume decreases.Temperature = Volume

  12. P1V1 = P2V2 T1 T2Temperature is measured in K°(Kelvin). 273° K = 0° C = 32° F

  13. The pressure of a gas remains constant at 10 Pa and the temperature changes from 273°K to 283°K. The volume starts at 20 L. What is the volume after this temperature increase?

  14. P1V1= P2V2 T1 T2 (10 Pa) (20 L) = (10 Pa) (? L) 273°K 283°K 0.732 = 0.0353 (?L) 0.732 /0.0353 = (?L) V2 = 20.7 L

  15. The temperature of a gas remains constant at 300 °K and the pressure changes from 5 Pa to 10 Pa. The volume starts at 20 L. What is the volume after this pressure increase?

  16. P1V1= P2V2 T1 T2 (5 Pa)(20 L) = (10 Pa)(? L) 300°K 300°K 0.333 = 0.0333 (?L) 0.333/0.0333 = 10 L

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