1 / 9

Energy Transformations

Energy Transformations . Arbaaz Khan Quinn Calvert Rishi Savaliya Rishant Dwivedi. Chemical → Electrical . Chemical= m x SE m= Mass of Chemical (Kg) SE= Specific Energy (MJ/Kg) .045 x 500,000=22500J 22500J = 22.5KJ. Electrical = IV/t I= Current (Amps) V= Voltage (Volts)

ronia
Télécharger la présentation

Energy Transformations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Energy Transformations Arbaaz Khan Quinn Calvert Rishi Savaliya RishantDwivedi

  2. Chemical → Electrical • Chemical= m x SE • m= Mass of Chemical (Kg) • SE= Specific Energy (MJ/Kg) • .045 x 500,000=22500J • 22500J = 22.5KJ • Electrical = IV/t • I= Current (Amps) • V= Voltage (Volts) • t= time (seconds) • (.0038 x 8.52)/.539=.06J Efficiency = .06/22500 = .00267%

  3. Electrical → Rotational • Electrical = .06J • Rotational = ½Iω2 = ½ .0000245(25) = .007656 J • I = Moment of Inertia (kg*m) • Moment of Inertia = mr2 = 0000245 (Kg*m) • m = mass (Kg) • r = radius (meters) • ω = Angular Velocity (revs/s) • Angular Velocity = θ/t = 25 (revs/s) • θ = angular displacement (rads/revs) • t = time (seconds) Efficiency = .00001964/.069 = .0285 %

  4. Transformation Video:Electrical → Rotational

  5. Rotational → Wind • Rotational Energy = .007656 Joules • Wind Energy == ½(1.172)(3.1293)3()(.035)2 = .69 J • = Air Density (kg*m3) = 1.172 kg*m3 • = Velocity (m/s) = 3.1293 m/s • = Radius (m) = .035m Efficiency = .069/.007656 = 11%

  6. Wind → Kinetic1 • m = mass • v = velocity Efficiency = .00001964/.069 = .0285 %

  7. Potential → Kinetic2 • m = mass • g = acceleration of gravity • h = height • m=mass • v=velocity=x/t • X=Distance • t=time Efficiency = .018/(.557+.00001964) = 3.23%

  8. Overall Efficiency • Efficiency = Wout/Win = .018/(22500+.557) = .00008% • Ein= 22500J • Eout= .018J

  9. References The Engineering Toolbox. (n.d.). Retrieved February 13, 2011, from Engineering Toolbox website: http://www.engineeringtoolbox.com/ Battery energy -- What battery provides more? (n.d.). Retrieved February 17, 2011, from AllAboutBatteries.com website: http://www.allaboutbatteries.com/Battery-Energy.html Lithium. (n.d.). Retrieved February 17, 2011, from Duracell website: http://www1.duracell.com/procell/chemistries/lithium.asp

More Related