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Aromatic Substitution

Aromatic Substitution

Aromatic Substitution. Chapter 22. Reading Assignment. Sections 22.0 through 22.2 Sections 22.4 through 22.9 Sections 22.10 through 22.12 Section 22.17 Section 22.18 (chapter summary) Problems. Assigned Problems. In-text problems 22-1 through 22-2 22-4 through 22-13

By Pat_Xavi
(390 views)

Geometry Prediction

Geometry Prediction

Geometry Prediction. Ray A. Gross, Jr. Prince George’s Community College April 18, 2007. Nature of Bonding. Central Atom (CA) Ligands (L) Lone Pairs (LPCA). G. N. Lewis Linus Pauling. 1930. 1931. Water (H 2 O). Sulfuric Acid (H 2 SO 4 ). Note: L = # s bonds to CA .

By Albert_Lan
(277 views)

Which of the following is a soluble, strong base?

Which of the following is a soluble, strong base?

Which of the following is a soluble, strong base?. RbOH NH 3 Al(OH) 3 Co(OH) 3 Co(OH) 2. Which salt is produced from a strong acid and a strong base?. NH 4 Cl NaClO KClO 3 Na 2 CO 3 LiNO 2.

By joshwa
(281 views)

Acid – Base Titration

Acid – Base Titration

Acid – Base Titration. Prelab question. M A x #H x V A = M B x #OH x V B M A = 6 M, #H = 2, V A = ? M B = 0.5 M, #OH = 1, V B = 0.5 L (6 M)(2)(V A ) = (0.5 M)(1)(0.5 L) V A = (0.5 M)(1)(0.5 L) / (6 M)(2) V A = 0.25 mol / 12 M = 0.0208 L = 2 0.8 mL.

By zytka
(245 views)

Chapter 23 Metals & Metallurgy

Chapter 23 Metals & Metallurgy

Chemistry: A Molecular Approach , 1 st Ed. Nivaldo Tro. Chapter 23 Metals & Metallurgy. Roy Kennedy Massachusetts Bay Community College Wellesley Hills, MA. 2008, Prentice Hall. General Properties and Structure of Metals. opaque good conductors of heat and electricity

By tuan
(199 views)

Balancing Equations

Balancing Equations

Balancing Equations. H 2 + Cl 2 → HCl. Balancing Equations. KI + Br 2 → KBr + I 2. Balancing Equations. CH 4 + O 2 → CO 2 + H 2 O. Balancing Equations. V 2 O 5 + Ca → V + CaO. Balancing Equations. NaCl + F 2 → NaF + Cl 2. Using Mole Ratios.

By garnet
(347 views)

PLASMA GASIFICATION FOR VOC DESTRUCTION

PLASMA GASIFICATION FOR VOC DESTRUCTION

Debanjan Das Amrita Mukherjee Chethan Kumar Gaddam Ganesh Rahul Bhimanapati. PLASMA GASIFICATION FOR VOC DESTRUCTION . Problem Statement.

By mills
(426 views)

Naming Acids

Naming Acids

Naming Acids. Chemistry 11 Mrs. Kay. Acids. When these compounds dissolve in water they produce hydrogen ions. The concentration of hydrogen ions produced is related to its molarity (simple ratios) HCl  H + + Cl - 2M 2M 2M

By oberon
(172 views)

Acid – Base Titration

Acid – Base Titration

Acid – Base Titration. Prelab question. M A x #H x V A = M B x #OH x V B M A = 6 M, #H = 2, V A = ? M B = 0.5 M, #OH = 1, V B = 0.5 L (6 M)(2)(V A ) = (0.5 M)(1)(0.5 L) V A = (0.5 M)(1)(0.5 L) / (6 M)(2) V A = 0.25 mol / 12 M = 0.0208 L = 2 0.8 mL.

By rosalba
(121 views)

ORGANIC REACTIONS

ORGANIC REACTIONS

CHEM 353. BRIEF REVIEW. OF. ORGANIC REACTIONS. METHODS OF SYNTHESIS FOR THE MAJOR FUNCTIONAL GROUPS OF ORGANIC CHEM. THIS SET OF SLIDES IS STILL UNDER CONSTRUCTION. PLEASE BE PATIENT. ACID HALIDES. SYNTHESIS OF ACID CHLORIDES. thionyl chloride. + SO 2. + HCl.

By thor
(220 views)

Put these into different groups, as many as you can think of

Put these into different groups, as many as you can think of

Put these into different groups, as many as you can think of. Groups. Compounds & elements Green & blue Ones that were gases & others at rm temp Group 7 & others. Objectives I want you to be able to . Explain why heating to constant mass is important in an experiment

By rafiki
(129 views)

If 150.0 mL of 0.100 M HBr and 50.0 mL of 0.100 M KOH solutions are mixed, what are the molarities of the ions in th

If 150.0 mL of 0.100 M HBr and 50.0 mL of 0.100 M KOH solutions are mixed, what are the molarities of the ions in th

If 150.0 mL of 0.100 M HBr and 50.0 mL of 0.100 M KOH solutions are mixed, what are the molarities of the ions in the resulting solution?. 0.0750 M in H + , 0.0750 M in Br - , 0.0250 M in K + 0.0500 M in H + , 0.0750 M in Br - , 0.0500 M in K +

By aminia
(0 views)

The Activity Series

The Activity Series

The Activity Series. Text Reference: 3.3 (pg. 125 - 128). No, Ni is below Na. Yes, Li is above Zn. Yes, Al is above Cu. Yes, Fe is above Cu. We have looked at several reactions: Fe + CuSO 4  Cu + Fe 2 (SO 4 ) 3 Li + H 2 O  LiOH + H 2

By jacob
(0 views)

S1 L5 Surgical dressings

S1 L5 Surgical dressings

S1 L5 Surgical dressings. Anna Drew. NOTES : Linked with carbohydrates (Semester 3 of pharmacognosy) Traditionally plant fibres were used With recent advances in wound-healing many materials of non-vegetable origin are now used. Surgical dressings & sutures. Composed of fibres

By Jimmy
(307 views)

Rates of Reaction

Rates of Reaction

Rates of Reaction. 8H + + C 2 O 4 2- + MnO 4 -  Mn 2+ + 4H 2 O + CO 2 H 2 SO 4 , H 2 C 2 O 4 (oxalic), KMnO 4 provide ions. Read 18.1 pg. 737-738 Demonstration of variations in reaction rates: Ca vs. Na vs. Li in water to produce H 2 gas Flour burning in air.

By fell
(193 views)

The Activity Series

The Activity Series

The Activity Series. K. Na. Li. No, Ni is below Na. Ca. Yes, Li is above Zn. Mg. Al. Zn. Yes, Al is above Cu. Fe. Ni. Sn. Pb. Yes, Fe is above Cu. H. Cu. Hg. Ag. Au. We have looked at several reactions: Fe + CuSO 4  Cu + Fe 2 (SO 4 ) 3 Li + H 2 O  LiOH + H 2

By taariq
(269 views)

POULTRY GUARD FOR AMMONIA CONTROL

POULTRY GUARD FOR AMMONIA CONTROL

POULTRY GUARD FOR AMMONIA CONTROL. Technical Department Bedson Africa. WHAT IS POULTRY GUARD. It is an absorbent clay carrier loaded with pure concentrated sulfuric acid. ADVANTAGES OF POULTRY GUARD. It delivers consistent ammonia control. It does not require moisture during application.

By gautam
(16 views)

Pharmaceutical Medicinal Chemistry-1

Pharmaceutical Medicinal Chemistry-1

Pharmaceutical Medicinal Chemistry-1. Dr. Bilal Al- jaidi. Medicinal Chemistry. Is the science that deals with the design and development of pharmaceutical agents that has a desired biological effect on human body and other living systems. Drug.

By emily
(983 views)

Solution Chemistry

Solution Chemistry

Solution Chemistry. It’s all about the concentration. Common units of concentration. % by mass – g solute /100 g solution % by volume – mL solute/100 mL solution % by mass-volume – g solute/100 mL solution Molarity – moles solute/L solution Molality – moles solute/kg solvent

By eulalie
(182 views)

Hess’s Law

Hess’s Law

Hess’s Law. Hess’s Law. Hess’s Law states that the enthalpy change for a reaction is independent of the reaction pathway and depends only on the concentration of reactants . Examples. Combustion of Glucose The enthalpy change for the direct combustion of 1 mol glucose in one step

By keagan
(164 views)

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