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Higher Quadratic Past Paper Q uestions. Higher Quadratic Past Paper Questions. a = 1 1 x 2 – 5 x + (k + 6) = 0 b = – 5 c = (k + 6) Equal roots b 2 – 4ac = 0 ( – 5 ) 2 – 4( 1 ) (k + 6) = 0 25 – 4k – 24 = 0 1 – 4k = 0 1 = 4k k = ¼.

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## Higher Quadratic Past Paper Q uestions

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**Higher Quadratic Past Paper Questions**a = 1 1x2 – 5x + (k + 6) = 0 b = – 5 c = (k + 6) Equal roots b2 – 4ac = 0 (– 5)2 – 4(1)(k + 6) = 0 25 – 4k – 24 = 0 1 – 4k = 0 1 = 4k k = ¼ 2001 Paper I Q2 For what values of k does the equation x2 – 5x + (k + 6) = 0 have equal roots? 3**a = 1 – 2k (1 – 2k)x2 – 5kx – 2k = 0**b = – 5k c = - 2k Real roots b2– 4ac ≥ 0 (– 5k)2– 4(1 – 2k)(– 2k)≥ 0 25k2 + 8k(1 – 2k) ≥ 0 25k2+ 8k – 16k2 ≥ 0 9k2+ 8k ≥ 0 For all integers 9k2 ≥ 0 & 9k2 ≥8k always real roots for all integer values of k. Higher Quadratic Past Paper Questions 2002 Paper 2 Q9 Show that the equation (1 – 2k)x2 – 5kx – 2k = 0 has real roots for all integer values of k? 5**x2 + 3x + 4 = 2x + 1**a = 1 x2 + x + 3= 0 b = 1 c = 3 Find value of b2– 4ac (1)2– 4(1)(3) = 1 – 12 = -11 < 0 As b2 – 4ac < 0 No intersection occurs. Higher Quadratic Past Paper Questions 2003 Paper 1 Q7 Show that the line with equation y = 2x + 1 does not intersect the parabola with equation y = x2 + 3x + 4 5**x3 + px2 + px + 1 = 0**1 p p 1 -1 As Remainder, R = 0 x = -1 is a solution & x3 + px2 + px + 1 = (x + 1)(1x2 + (p – 1)x + 1) Higher Quadratic Past Paper Questions -1 1–p -1 2005 Paper 2 Q11 Show that x = -1 is a solution of the cubic x3 + px2 + px+ 1 = 0 1 Hence find the range of values of p for which all the roots are real 7 1 P–1 1 0 1**From (a)**x3 + px2 + px + 1 = (x + 1)(1x2 + (p – 1)x + 1) a = 1 If real then b2 – 4ac ≥ 0 b = (p – 1) c = 1 (p – 1)2 – 4(1)(1)≥ 0 p2– 2p + 1– 4 ≥ 0 p2 – 2p – 3 ≥ 0 (p – 3)(p + 1) ≥ 0 Real when p ≤ -1 & p ≥ 3 Higher Quadratic Past Paper Questions y 2005 Paper 2 Q11 (b) Hence find the range of values of p for which all the roots are real 7 x -1 3 7**2x2 + 4x – 3 = 2[x2 + 2x – 3/2]**= 2[(x2 + 2x + 1) – 1 – 3/2] = 2[(x2 + 2x + 1) – 2/2 – 3/2] = 2[(x + 1)2 – 5/2] = 2(x + 1)2 – 5 Happy as + x2 (- 1, - 5) is Min Tpt Higher Quadratic Past Paper Questions 2006 Paper 1 Q8 Express 2x2 + 4x – 3 in the formf(x) = a(x + b)2 + c 3 Write down the coordinaates of the turning point 1 4**a = k kx2 – 1x – 1= 0**b = -1 c = -1 b2– 4ac < 0 No Real Roots (-1)2– 4(k)(-1)< 0 1 + 4k< 0 4k< – 1 k< – ¼ Higher Quadratic Past Paper Questions 2007 Paper 1 Q4 Find the range of values of k such that the equation kx2 – x – 1 = 0 has no real roots 4**a = 1 1x2 + 1x + 1= 0**b = 1 c = 1 Find nature of b2– 4ac (1)2– 4(1)(1)= 1 – 4 = -3 < 0 As b2– 4ac < 0 Non real roots are not equal or real A – Neither (1) or (2) are true Higher Quadratic Past Paper Questions 2008 Paper 1 Q10 Which of the following are true about the equation x2 + x + 1 = 0 (1) The roots are equal (2) The roots are real A = Neither B = (1) Only C = (2) Only D = Both are True 2**y**Higher Quadratic Past Paper Questions • Use roots at x = 1 & x = 4 for factors • y = k(x – 1)(x – 4) • 12 = k(0– 1)(0 – 4) • 12 = k(-1)(-4) • 4k = 12 • k = 3 • y = 3(x– 1)(x – 4) • A 12 x 1 4 2008 Paper 1 Q13 The graph has an equation of the form y = k(x – a)(x – b). What is the equation of the graph 2**2x2 + 4x + 7 = 2[x2 + 2x + 7/2]**= 2[(x2 + 2x + 1) – 1 + 7/2] = 2[(x2 + 2x + 1) – 2/2 + 7/2] = 2[(x + 1)2 + 5/2] = 2(x + 1)2 + 5 = 2(x + p)2 + q q = 5 = A Higher Quadratic Past Paper Questions 2008 Paper 1 Q16 2x2 + 4x + 7 is expressed in the form 2(x + p)2 + q What is the value of q? 2 2**(a) x2 – 10x + 27 = (x2 – 10x + 25) – 25+ 27**= (x – 5)2 + 2 Increasing Differentiate g(x) = 1/3 x3 – 5x2 + 27x – 2 (b) g’(x) = x2– 10x + 27 ** Use answer to (a) = (x – 5)2 + 2 (x – 5)2 + 2 > 0 for all x function is always increasing Higher Quadratic Past Paper Questions 2006 Paper 1 Q8 Write x2 – 10x + 27 in the form (x + b)2 + c 2 Hence show that g(x) = 1/3 x3 – 5x2 + 27x – 2 is always increasing 4 6**Higher Quadratic Past Paper Questions**Total = 41 Marks

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