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Jawaban : soal kehilangan BT Prategang Tahap 1 Dari Waktu penarikan awal tendon s/d

Jawaban : soal kehilangan BT Prategang Tahap 1 Dari Waktu penarikan awal tendon s/d transfer pada 48 jam ti = 1/24 hari t = 2 hari fst = 0.75 x fpu = 0.75x 1862 Mpa =1396 Mpa fsi / fst = 0.75x 1862 / 0.85 x 1862 = 0.882 > 0.55 ( oke ) Relaksasi:

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Jawaban : soal kehilangan BT Prategang Tahap 1 Dari Waktu penarikan awal tendon s/d

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  1. Jawaban : soal kehilangan BT Prategang Tahap 1 Dari Waktu penarikan awal tendon s/d transfer pada 48 jam ti = 1/24 hari t = 2 hari fst = 0.75 x fpu = 0.75x 1862 Mpa =1396 Mpa fsi / fst = 0.75x 1862 / 0.85 x 1862 = 0.882 > 0.55 ( oke ) Relaksasi: RET = 1396 x { (log 48 - log 1) / 10 } x ( 0882 -0.55) =77,9 Mpa (1) = 11,30 Ksi Elastisitas (ES ): Misalkan ES =92,4 Mpa ; fs t = 1396 Mpa - 77,9 Mpa - 92,4 Mpa = 1226 Mpa F = 1226 N / mm 2 x 1975 mm 2 = 2421350 N = 2421 KN Teg Beton yg terjadi tepat pd tendon 44

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