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Understanding Segment Relations: Properties of Equality and Proof Justifications

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7 diapositives · 303 Views · Oct 15, 2014

In this section, we delve into the essential properties of equality that underlie geometric proofs concerning segments. We explore the Substitution, Division, Transitive, and Symmetric properties with illustrative examples. The congruence of segments is established through reflexive, symmetric, and transitive properties. Each proof is broken down step-by-step, showcasing how to apply these properties effectively to justify mathematical statements. Mastering these concepts is crucial for advancing in geometric reasoning and proofs.

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  1. Chapter 2Section 5 Verifying Segment Relations

  2. Warm-Up • Name the property of equality that justifies each statement. • 1) If 3x = 15 and 5y = 15, then 3x = 5y •  Substitution Property of Equality • 2) If 4z = -12, then z = -3 • Division Property of Equality • 3) If AB = CD, and CD = EF, then AB = EF • Transitive Property of Equality • 4) If 45 = m<A, then m<A = 45 • Symmetric Property of Equality

  3. Vocabulary • Theorem 2-1: Congruence of segments is reflexive, symmetric, and transitive.

  4. Example 1) Justify each step in the proof. P Q R S Given: Points P, Q, R, and S are collinear. Prove: PQ = PS – QS Points P, Q, R, and S are Collinear Given PS = PQ + QS Segment Addition Postulate PS – QS = PQ Subtraction Property of Equality PQ = PS - QS Symmetric Property of Equality

  5. Example 2) Justify each step in the proof. A B C D Given: Line ABCD Prove: AD = AB + BC + CD Line ABCD Given AD = AB + BD Segment Addition Postulate BD = BC + CD Segment Addition Postulate AD = AB + BC + CD Substitution Property of Equality

  6. Example 3) Fill in the blank parts of the proof. A B C Given: AC is congruent to DF AB is congruent to DE Prove: BC is congruent to EF D E F AC is congruent to DF; AB is congruent to DE Given AC = DF; AB = DE Definition of congruent segments AC – AB = DF – DE Subtraction Property of Equality AC = AB + BC; DF = DE + EF Segment Addition Postulate AC – AB = BC; DF – DE = EF Subtraction Property of Equality DF – DE = BC Substitution Property of Equality BC = EF Substitution Property of Equality BC is congruent to EF Definition of congruent segments

  7. Example 4) Fill in the blank parts of the proof. A Given: AB is congruent to XY BC is congruent to YZ Prove: AC is congruent to XZ X Y Z B C AB is congruent to XY; BC is congruent to YZ Given AB = XY BC = YZ Definition of congruent segments AB + BC = XY + YZ Addition Property of Equality AB + BC = AC XY + YZ = XZ Segment Addition Postulate AC = XZ Substitution Property of Equality AC is congruent to XZ Definition of congruent segments