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Counter state machine

Counter state machine. A counter counts Number of elements in counter determines how many different states we need For example, an eight-state counter can count eight steps. X= Y= Z=. Another counter. Counter need not have always number of states that is equal to a power of 2

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Counter state machine

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  1. Counter state machine • A counter counts • Number of elements in counter determines how many different states we need • For example, an eight-state counter can count eight steps X= Y= Z=

  2. Another counter • Counter need not have always number of states that is equal to a power of 2 • Here is a five state counter • Is it simpler? X= Y= Z=

  3. And what about output • Output in a state may depend on state or state and input • Mealy machine: Output depends on both current state and current input • Moore machine: Output depends on current state • Thus we have two different circuits to implement • 1. Decides what is the next state • 2. Decides what is the output • Both circuits are combinational • States are remembered by memory elements • Latches and Flips-flops are used to remember states

  4. O U T P U T S I N P U T S Next State Logic Output Logic Overall structure of a State machine • The two sets of circuits are shown • Next state logic determines next step based on current state and next input • Output logic determines the output based on current state • Mealy machine will have slight different structure

  5. Example • Design a state machine that will repeatedly display in binary values 1, 3, 5, and 7 • Solutions: • How many states we need? • What is the state transition diagram? • What is the output in each state? • What is the next state logic? • Construct the truth table with state variables • Derive the output logic • Draw the circuit

  6. S0 S1 S2 S3 Example (contd.) • We need four states, S0, S1, S2, S3 • State transitions diagram is • State transition table, implementation level state transition table, output table, and implementation level output tables are • And the logic equations are L2 = XY’+XY = X X := X’Y+XY’ L1 = X’Y+XY = Y Y := X’Y’+XY’ = Y’ L0 = X’Y’+X’Y+XY’+XY = X’+X = 1

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