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Announcements. Homework for tomorrow… (Ch. 32, CQ 9, Probs . 34 & 48) 32.8: 2.5A, 250A, 5.0 x 10 3 - 5.0 x 10 4 A, 5.0 x 10 5 A 32. 11 : a) 20 A b) 1.6 x 10 -3 m 32.14: a) (6.7 x 10 -5 T) khat b ) –(2.0 x 10 -4 T) khat c) (6.7 x 10 -5 T) khat Office hours…

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**Announcements**• Homework for tomorrow… (Ch. 32, CQ 9, Probs. 34 & 48) 32.8: 2.5A, 250A, 5.0 x 103 - 5.0 x 104 A, 5.0 x 105 A 32.11: a) 20 A b) 1.6 x 10-3 m 32.14: a) (6.7 x 10-5 T) khat b) –(2.0 x 10-4 T) khat c) (6.7 x 10-5 T) khat • Office hours… MW 12:30-1:30 pm TR 9-10 am F 10-11 am • Tutorial Learning Center (TLC) hours: M 8-1 pm, 3-6 pm, W 8-1 pm, 2-6 pm TR 8-6 pm, F 8-2 pm**Chapter 32**The Magnetic Field (The Magnetic Force on a Moving Charge & on a Current-Carrying Wire)**Review…**The B-field of a current loop of radius R carrying a current I, when z >>R… Force on a charged particle with a velocity v in a B-field …**Cyclotron Motion**Consider a charged particle moving perpendicular to a uniformB-field… • Since F is perpendicular to v, the charge particle undergoes uniform circular motion. The radius of the orbit is… The frequency of revolution is…**Cyclotron Motion**Consider a charged particle moving perpendicular to a uniformB-field… • Since F is perpendicular to v, the charge particle undergoes uniform circular motion. The radius of the orbit is… The frequency of revolution is…**i.e. 32.11: The radius of cyclotron motion**In the figure below, an electron is accelerated from rest through a potential difference of 500 V, then injected into a uniform B-field. Once in the B-field, it completes half a revolution in 2.0 ns. What is the radius of its orbit?**Cyclotron Motion**What if v is NOT perpendicular to B? The component of v parallel to B is NOT affected by the field. The component of vperpendicular to B determines the radiusof the helix.**Quiz Question 1**Which B-field (if it’s the correct strength) allows the electron to pass through the charged electrodes without being deflected?**32.8: Magnetic Forces on Current-Carrying Wires**Consider a current-carrying wire perpendicular to the B-field… Each charge in the current has a force of magnitude qvB directed to the left. What is the force on the wire?**32.8: Magnetic Forces on Current-Carrying Wires**Consider a current-carrying wire perpendicular to the B-field… Each charge in the current has a force of magnitude qvB directed to the left. What is the force on the wire? Magnitude: Direction: RHR**Quiz Question 2**The horizontal wire can be levitated – held up against the force of gravity – if the current in the wire is • Right to left. • Left to right. • It can’t be done with this magnetic field.**Force Between Two Parallel Wires**What is the force on wire1 due to wire2?**Force Between Two Parallel Wires**What is the force on wire1 due to wire2?

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