1 / 12

Exponential Function

Exponential Function. y = a x. If we look at the graphs of y = a x for different values of a, we can see that the gradient of the exponential graph increases as the value of a increases a  gradient . y = a x. a increasing. Gradient of y = 2 x at (0,1) is 0.693

angus
Télécharger la présentation

Exponential Function

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Exponential Function

  2. y = ax If we look at the graphs of y = ax for different values of a, we can see that the gradient of the exponential graph increases as the value of a increases a  gradient 

  3. y = ax a increasing

  4. Gradient of y = 2x at (0,1) is 0.693 • Gradient of y = 3x at (0,1) is 1.099 • So there must be a value (between 2 and 3) where the gradient at (0,1) is exactly 1 • This number is 2.71828… and is called e

  5. Natural Logarithms

  6. By drawing the graph of y = ex we can see that there is an inverse function

  7. If y = ex Take logs of both sides logey = logeex logey = xlogee but logee = 1 So x = logey Interchanging x and y gives y = logex (written as y = lnx) This is the inverse function

  8. Questions 1. Make x the subject of lnx – lnA = kt 2. Make t the subject of s = e-kt 3. Make x the subject of y-5 = (A - 5)ex

  9. Questions • A colony of human settler on a previously uninhabited planet. After t years, their population, P, is given by P = 100e0.056t a. Sketch the graph of P against t b. How many settlers were there planet initially? c. How long does it take for the population to reach 1 million?

  10. Answers • lnx – lnA = ktln(x/A) = kt x/A = ekt x = Aekt • s = e-ktlns =-kt t =-lns/k 3. y-5 = (A - 5)ex ex =(y-5)/(A - 5) x =ln((y-5)/(A - 5))

  11. Answers ctd • P = 100e0.056t • When t= 0P = 100e0 = 100 c. P = 100e0.056t = 1,000,000 e0.056t = 10,000 0.056t = ln 10,000= 9.2103 t = 9.2103/0.056 = 164.47 .47 years =12x.47 months = 5.64months It takes 164.5 years to 4 s.f. or 164 years 6 months to the nearest month

More Related