1 / 36

Power Amplifiers

Power Amplifiers. Unit – 4.1. Classification of Power Amplifiers. Power amplifiers are classified based on the Q point If the operating point is chosen at the middle of the load line, it is called Class A amplifier

axl
Télécharger la présentation

Power Amplifiers

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Power Amplifiers Unit – 4.1

  2. Classification of Power Amplifiers • Power amplifiers are classified based on the Q point • If the operating point is chosen at the middle of the load line, it is called Class A amplifier • If the operating point is chosen at the cut-off point it is called Class B amplifier • If the operating point is chosen beyond the cut-off point it is called Class C amplifier • It conducts for 3600

  3. Class A amplifier • The Q point is chosen at the middle of load line • This will give equal swing on either direction • Both halves of the input comes at the output • Hence Class A will give (amplitude) distortionless output • It can handle only small signals • Its efficiency is less

  4. 10mA Ic B 6mA Ib = 60μA 10mA 4mA Ib = 50μA 8mA Q Ib = 40μA 6mA Ib = 30μA 4mA Ib = 20μA 2mA A Vce 0 V 24 V Class A

  5. Class B amplifier • The Q point is chosen at the cut-offpoint • This will give swing only on one direction • Only one half of the input comes at the output • Hence Class B will give (amplitude) distorted output • It can handle large signals • Its efficiency is high • It conducts for 1800

  6. 10mA Ic Ib = 60μA 10mA Ib = 50μA 8mA Ib = 40μA 6mA Ib = 30μA 0mA 4mA Ib = 20μA 2mA Q Vce 0 V 24 V Class B

  7. Class C amplifier • The Q point is chosen at the beyond the cut-offpoint • This will give only a partial swing in one direction • Only a portion of the input comes at the output • Hence Class C will give (amplitude) severely distorted output • It can handle large signals • It conducts for less than 1800

  8. 10mA Ic Ib = 60μA 10mA Ib = 50μA 8mA Ib = 40μA 6mA Ib = 30μA 0mA 4mA Ib = 20μA 2mA Q` Vce 0 V 24 V Class C

  9. Class A Class B Class C

  10. Distortionless amplifier • Out of the 3 amplifiers, Class C is unsuitable as the distortion is very heavy • Class A is the best, as it gives distortionless output • But Class A cannot handle large signals as required by the Power Amplifier • Though Class B gives heavy distortion, it gives out one half of the signal perfectly • And Class B can handle large signals

  11. Class A Audio Amplifier • As we have seen out of the 3 classifications, Class A is the best, as it does not give any distortion • Among the configurations, we know that CE is the best as it gives maximum power gain • A CE amplifier will have high output impedance • Unfortunately for an audio amplifier, the output device is the speaker which has a low impedance

  12. Impedance Matching • The speaker impedance is typically about 4 Ω • Hence there is a mismatch between the high Zo of the amplifier and the low impedance of the speaker • This will result in loss of gain • This can be avoided by connecting a transformer at the output stage • The primary winding will match the high Zo of the amplifier while the secondary will match the low impedance of the speaker

  13. Class A Audio Amplifier Vcc Rb1 Rb1 Rc 270 K 5.6 K 270 K Rb2 Re Rb2 Re Ce Ce

  14. Drawback • The drawback of this circuit is that it cannot handle large signals • In a Class A amplifier, the operating point is chosen around the middle of the load line • If the signal exceeds the cut-off point, the output current stops and any signal with a lower amplitude will not come at the output • Similarly, if the signal exceeds the saturation point, the output current cannot increase any further, even if the input signal increases

  15. Class A Ic B Ib = 60μA 10mA Ib = 50μA 8mA Q Ib = 40μA 6mA Ib = 30μA 4mA Ib = 20μA 2mA A Vce 0 V 24 V

  16. Class B Push-Pull Amplifier • To avoid this we can use Class B which has a greater signal handlingcapacity • But Class B will give only one half of the signal • Hence we can use 2 Class B amplifiers • One for one half and one for the other half • This type of amplifier is called Push-Pull Amplifier

  17. Vcc T1 TR1 TR2 T3 T2 Class B Push-Pull

  18. Push-Pull Circuit • TR1 and TR2 are output transistors connected back to back, with their emitters grounded • The output transformerTR1 couples the push-pull output to the speaker • In the Push-Pull arrangement T1 conducts for one half of the signal & T2 conducts for the other half • Both are biased in Class B and each gives one half of the signal & the combined output is coupled to the speaker

  19. Push-Pull Circuit • The Driver TransformerTR2 gives 2 out of phase signals • During one half, the +ve half forward biases T1 while the –ve half reverse biases T2 • Thus when T1 conducts, T2 is cut-off & vice-versa • This way both the transistors conduct alternately to give the full signal output

  20. Class D Amplifier • During the +ve half cycle Q1 gets Forward Bias and it conducts • During the -ve half cycle Q2 gets Forward Bias and it conducts • Thus both the transistors conduct alternately • The amplifier works for 3600 • No distortion • 100% efficiency

  21. Vcc T1 TR1 TR2 T3 T2 Working of Push-Pull Circuit • During the first half T1 conducts • Ic flows from the centre-tapping through T1 to ground • This half is coupled to the speaker through TR1

  22. Vcc T1 TR1 TR2 T3 T2 Working of Push-Pull Circuit • During the second half T2 conducts • Ic flows from the centre-tapping through T2 to ground • This half is coupled to the speaker through TR1

  23. Drawbacks • Though this circuit functions well it has a few drawbacks • Transformer coupling affects the quality of output • Phase shifting circuit is a must • Both these drawbacks can be avoided if we use one pair of PNP and NPN transistors at the output

  24. Complementary Symmetry Amplifier Vcc T1 T2

  25. Complementary Symmetry Amplifier • This circuit uses one NPN transistor & one PNP transistor at the output stage • During the +ve half, T1(NPN) base gets forward bias & it conducts while T2 (PNP) gets reverse biased and does not conduct • This gives one half of the signal at the speaker coupled to the emitter

  26. Complementary Symmetry Amplifier • During the other half, T2 gets forward bias and conducts while T1 gets reverse biased and does not conduct • Thus T1 & T2 conduct alternately giving a distortionless output • This circuit does not require a phase shifter

  27. Cross – over distortion • Class B Push-Pull amplifier has one limitation • As the phase of the signal changes from +ve to –ve (or vice-versa) one transistor stops conducting while the other begins conducting • But the transistor cannot conduct instantaneously as it requires a minimum Vbe before it starts conducting • Thus as the signal crosses over zero, a distortion occurs • This is called Cross over distortion

  28. Cross – over distortion Vbe -Vbe

  29. Class AB amplifier • This circuit overcomes cross-over distortion • Biasing is done such that even if there is no input signal, a small current keeps the output transistor conducting • This circuit uses 2 diodes whose characteristics matches with that of the BE junction of the output transistors • Biasing resistors R1 & R2 are also identical values

  30. Class AB amplifier Vcc R1 T1 D1 D2 T2 R2

  31. Symmetrical components • Since R1 & D1 are identical to R2 & D2, the diode junction as well as the output point will be at half the supply voltage • Because of symmetry both T1 & T2 will conduct equally • Even when there is no input signal, there will be a current Icq = (I/2 Vcc – 0.6) / R1 • This will keep the output transistors conducting

  32. Elimination of cross-over distortion • Normally, during cross-over there will not be any output till the non-conducting transistor gets the minimum Vbe • This causes distortion • This has been eliminated here, since the 0.6 V across the diodes keep the transistors on and gives a continuous output signal without producing cross-over distortion

  33. Thermal stability • In addition, the two diodes also provide thermal stability • They prevent the output transistors going to Thermal Run Away • When the output current is high, heat dissipation is more • The increase in temperature produces more charge carrier in the BE junction of T1 & T2

  34. This increases Ib & hence Ic • This in turn increases the power dissipation & hence the heat • This chain goes on till too much current flows and destroys the transistors • This is called Thermal Run Away • This is arrested by the diodes in the output circuit

  35. When the charge carriers increase in the B-E junction of T1 & T2, a similar increase takes place in D1 & D2, due to matching characteristics • This increase in the diode current, produces more drop across R1 & R2 and brings down the forward bias at the base of T1 & T2 • Thus the 2 diodes prevent cross-over distortion as well as provide thermal stability

  36. End of Unit – 4.1

More Related