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Daily Check

Daily Check. Homework Review. GPS Geometry Day 25 (9-11-13). UNIT QUESTION: What special properties are found with the parts of a circle? Standard: MMC9-12.G.C.1-5,G.GMD.1-3 Today’s Question: How can I find a segment length for a piece of a chord? Standard: MMC9-12.G.C.2.

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Daily Check

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  1. Daily Check

  2. Homework Review

  3. GPS GeometryDay 25 (9-11-13) UNIT QUESTION: What special properties are found with the parts of a circle? Standard: MMC9-12.G.C.1-5,G.GMD.1-3 Today’s Question: How can I find a segment length for a piece of a chord? Standard: MMC9-12.G.C.2

  4. How do you know when two chords are congruent? • corresponding arcs are congruent B A M P b. equidistant from the center L C LP  PM ALP = BMP = 90 D

  5. Flow Chart Proof

  6. 2x x + 40 2x = x + 40 x = 40

  7. In K, K is the midpoint of RE. If TY = -3x + 56 and US = 4x, find the length of TY. U T x = 8 TY = 32 K E R S Y

  8. IF AC is the perpendicular bisector of segment DB, then… D It’s the DIAMETER!!! Arcs DC and BC are congruent!!! A C B

  9. IN Q, KL  LZ. IF CK = 2X + 3 and CZ = 4x, find x. Q x = 1.5 C Z K L

  10. In P, if PM  AT, PT = 10, and PM = 8, find AT. P A M MT = 6 T AT = 12

  11. Your turn!  ÐUTV ÐXTW. Find WX.___________ 130º 11 Find ___________

  12. Your turn!  Find the length of each chord. 96 30 LN = _______ CE = _______

  13. Segment Lengths in Circles • Find the lengths of segments of chords • Find the lengths of segments of tangents and secants

  14. Secant and Tangent 2 Secants intersecet outside Chords intersect inside

  15. Two chords intersect INSIDE the circle Type 1: a ab = cd d c b

  16. Solve for x. 9 6 x x = 3 2

  17. 12 2x 8 3x Find the length of DB. x = 4 DB = 20 A D C B

  18. Find the length of each chord. D x = 8 AC = 13 DB = 14 A x - 4 x C 5 10 B

  19. Two secants intersect OUTSIDE the circle Type 2: E A B C D EA•EB = EC•ED

  20. Ex: 3 Solve for x. B 13 A 7 E 4 C x D 7 (7 + 13) = 4 (4 + x) x = 31 140 = 16 + 4x 124 = 4x

  21. Ex: 4 Solve for x. B x A 5 D 8 6 C E 6 (6 + 8) = 5 (5 + x) 84 = 25 + 5x x = 11.8 59 = 5x

  22. Type 2 (with a twist): Secant and Tangent C B E A EA2= EB • EC

  23. Ex: 5 Solve for x. C B x 12 E 24 A (12 + x) 242 = 12 x = 36 576 = 144 + 12x

  24. Ex: 6 5 B E 15 C x A (5 + 15) x2 = 5 x2 = 100 x = 10

  25. Homework Practice Worksheet

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