1 / 66

# Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9

Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9. Salt or Hydrolysis Reactions. Hydrolysis. Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products. Hydrolysis.

Télécharger la présentation

## Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9

E N D

### Presentation Transcript

1. Drill: Calculate the pH of 0.10 M H2Z in 0.50 M KHZ.Ka1 = 2.0 x 10-5 Ka2 = 5.0 x 10-9

2. Salt orHydrolysis Reactions

3. Hydrolysis Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products

4. Hydrolysis Water is added to decompose something

5. Hydrolysis MX + HOH HX + MOH

6. Salts

7. Salts • Ionic compounds that dissolve ~ 100 % in water

8. Salts of Acids • Salts of acids are negative • (A-)

9. Salts of Bases • Salts of bases are Positive • (M+ or B+)

10. Salt Solutions • When salts dissolve, their ions can recombine with water

11. Salt Solutions • The salts of weak acids can recombine with water producing basic solutions

12. Salt Solutions • The salts of weak bases can recombine with water producing acidic solutions

13. Salt Solutions • A- + H2O HA + OH- • B+ + H2O H+ + BOH

14. Drill: Calculate the salt/acid ratio of a solution of benzoic acid & sodium benzoate at a pH of 5.00.KaHBz = 6.4 x 10-5

15. Salt or Hydrolysis Problems

16. Salt Problem • Calculate the pH of a 0.20 M solution of NaBz • Ka HBz = 6.4 x 10-5

17. Drill: Calculate the pH of a solution of 0.10 M NH3 in 0.20 NH4Cl.Kb NH3 = 1.8 x 10-5

18. Salt or Hydrolysis Problems

19. Salt Problem • Calculate the pH of a 0.20 M solution of KNO2 • Ka HNO2 = 7.1 x 10-4

20. Salt Problem • Calculate the pH of a 0.10 M solution of R-NH3Cl • Kb R-NH2 = 2.5 x 10-5

21. Calculate the pH of a 0.18 M solution of KC2H3O2 • Ka = 1.8 x 10-5

22. Drill: Calculate the salt to acid ratio required to make a buffer solution with a pH of 4.495 using benzoic acid.KaHBz = 6.4 x 10-5

23. Salt Applications • Salts of strong acids & weak bases make acidic solutions

24. Salt Applications • Salts of strong bases & weak acids make basic solutions

25. Salt Applications • Salts of strong acids & strong bases make neutral solutions

26. Predict Relative pH • NaAc MnCl2 • KNO3 NH4Br • KHSO4 NH4Ac

27. Predict Relative pH • KAc NaCl • KClO2 NH4Cl • K2SO4 NaI

28. Anhydrides • Compounds without water; that when added to water, form other compounds

29. Acid Anhydrides • Non-metal oxides that form acids when added to water

30. Basic Anhydrides • Metal oxides that form bases when added to water

31. Predict Relative pH • Na2O SO2 • NO2 CO2 • CaO Al2O3

32. Calculate the pH of a 0.16 M solution of KC7H5O2 • Ka = 6.4 x 10-5

33. Calculate the pH of a solution of 0.0030 M KQ. • KaHQ = 3.0 x 10-5

34. Are there any questions on previous material?

35. A/B eq, Buffer & Salt Hydrolysis Problem

36. Calculate [H3PO4], [H2PO4-1], [HPO4-2], [PO4-3], [K+], [H+], & pH of 1.0 M KH2PO4 in 0.50 M K2HPO4. Ka1 = 7.5 x 10-3Ka2 = 6.2 x 10-8Ka3 = 4.2 x 10-13

37. You need to make a buffer solution with its greatest buffering capacity at pH ~ 5.4. In general terms, describe what acid or base you would chose, & how you would make the buffer.

38. 11.2 g of KOH was added to 2.0 L of 0.075 M H2CO3. Calculate the molarity of all ions present in the solution.Ka1 = 4.4 x 10-7Ka2 = 4.8 x 10-11

39. Drill: Calculate the pH of 0.10 M HF. Ka HF = 6.5 x 10-4

40. Test Review

41. Expect a straight acid/base problem like the drill

42. Calculate the pH of 0.10 M KF. Ka HF = 6.5 x 10-4

43. Predict Relative pH K2O MgO ClO2 (NH4)2O SO3 N2O3

44. Predict Relative pH • KAc NaCl • KClO2 NH4Cl • K2SO4 NaI

45. Calculate the pH of 5.0 M KCN. KaHCN= 5.0 x 10-10

46. Calculate pH of: 0.20 M MOHin 0.50 M MCl Kb = 5.0 x 10-5

47. Calculate pH of: 0.20 M MCl Kb = 5.0 x 10-5

48. Drill: Calculate the pH of0.20 M KQ. KaHQ = 8.0 x 10-5

More Related