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Algorithms for Enumerating All Spanning Trees of Undirected and Weighted Graphs. Sanjiv Kapoor and H.Ramesh. Presented by R97922102 李孟哲 R97922104 陳翰霖 R97922124 張仕明. Index. Introduction Computation Tree Algorithm 1 Algorithm 2 Algorithm 3. Introduction.
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Algorithms for Enumerating All Spanning Trees of Undirected and Weighted Graphs Sanjiv Kapoor and H.Ramesh Presented by R97922102 李孟哲 R97922104 陳翰霖 R97922124 張仕明
Index • Introduction • Computation Tree • Algorithm 1 • Algorithm 2 • Algorithm 3
Introduction • Spanning tree enumeration in undirected graphs is an important issue in network and circuit analysis • In this paper, author enumerate spanning trees by the computation tree • Every node in the computation tree represent a spanning tree
Algorithms Introduction • We use this way to enumerate all the spanning tree on undirected and weighted graphs. • Algorithm 1 • O(N+V+E) time • O(V2E) space • Algorithm 2 • O(N+V+E) time • O(VE) space • Algorithm 3 (with sorting) • O(NlogV+VE) time • O(N+VE) space
Spanning Tree • The original graph G
Spanning Tree • A Spanning tree of G
Spanning Tree • add a edge to the tree
Spanning Tree • get a cycle (fundamental cycle)
Spanning Tree • remove a edge on the cycle
Spanning Tree • get a new spanning tree of G
Spanning Tree • From this cycle, we can obtain several spanning trees.
Computation tree • First, we start off with a spanning tree T, and generate all other spanning trees form T by replacing edges in T by edges outside T • For every node x, Sx is the spanning tree corresponding to this node • To ensure that each spanning tree is generated exactly once, we use 2 edge set INx and OUTx for every node x
IN and OUT • The setINxconsist of edges which are always included in node x and it’s descendants • The set OUTx consist of edges which are always not included in node x and it’s descendants • The IN and OUT set of the root are both empty
1 1 3 3 2 2 4 4 5 5 In =[ ] Out=[ ] S =[ ] , , 1,2,4 Computation tree Arbitrary choose a spanning tree
1 1 3 3 2 2 4 4 5 5 In =[ ] Out=[ ] S =[ ] , , 1,2,4 Computation tree
1 1 3 3 2 2 4 4 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , , , , , , , , , , , , , , 1,2,4 Computation tree
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , , , , , , , , , , 1 1,2,4 2,4,5 1,2,4 1,2,5 1,4,5 3 4 2 5 Computation tree (-2,+5) (-1,+5) (-4,+5) 1 3 2 4 5
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , , , , , 5, 2, , 4, 1, 1 1,2,4 2,4,5 1,2,4 1,2,5 1,4,5 3 4 2 5 Computation tree (-2,+5) (-1,+5) (-4,+5) 1 3 2 4 5
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , 5, , 5, 5, 5, 2, , 4, 1, 1 1,2,4 2,4,5 1,2,4 1,2,5 1,4,5 3 4 2 5 Computation tree (-2,+5) (-1,+5) (-4,+5) 1 3 2 4 5
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , 5, , 5,2,1, 5,2, 5, 2, , 4, 1, 1 1,2,4 2,4,5 1,2,4 1,2,5 1,4,5 3 4 2 5 Computation tree (-2,+5) (-1,+5) (-4,+5) 1 3 2 4 5
1 1 3 3 2 2 4 4 5 5 In =[ ] Out=[ ] S =[ ] , 5, 1,2,4 Computation tree
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , , , , 5, 5, 5, 5,3 1,2,4 1,3,4 1,2,4 2,3,4 1 3 4 2 5 Computation tree (-1,+3) (-2,+3)
1 1 1 1 3 3 3 3 2 2 2 2 4 4 4 4 5 5 5 5 In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] In =[ ] Out=[ ] S =[ ] , 1,3, , 3, 5,1 5,2 5, 5,3 1,2,4 1,3,4 1,2,4 2,3,4 1 3 4 2 5 Computation tree (-1,+3) (-2,+3)
1 3 2 4 5 Computation tree
Appear not only once • The last son and its parent are the same
1 3 2 4 5 Another Computation tree C’(G) G C’(G) C(G)
Computation tree C(G)’s property • The son has zero or one edge differ from its parent. • The number of sons equals to the length of the fundamental cycle
Computation tree C’(G)’s property • The son has one edge differ from its parent. • The number of sons equals to the sum of the length of all fundamental cycles
Lemma 1 • The computation tree has at its internal nodes and leaves all the spanning trees of G • [Proof] • Following from induction and inclusion/exclusion principle • Let A be a node of computation tree C(G), B1,...,Bk+1 be the son of A
e1 A e2 f … • All spanning trees in B1,…, Bk contain edge f • All spanning trees in Bk+1 don’t contain edge f • The spanning trees as Bj ‘s descendants contain edges e1,…,ej-1, but the edge ej • e1,…,ek and f form a cycle B1 B2 Bk Bk+1 ek … … … … computation tree
The Algorithm 1 Generate a random spanning tree and initialize some data structures. … Prepare and modify the data structures. Recursively call the algorithm.
Possible problem in algorithm • How to maintain the IN , OUT, S ? • How to find the fundamental cycles?
Possible problem in algorithm • How to maintain the IN , OUT, S ? • S is easy, just add a edge and delete another one. • We use a data structure AG to maintain IN, OUT. • We would choose edges from AG • Initial: AG is the graph itself.
Possible problem in algorithm • Modify AG • Adding a edge into IN • Contract the edge 1 1 2 2 3 3
Possible problem in algorithm • Modify AG • Add a edge into OUT • Delete the edge 1 1 2 2 3 3
Modify the fundamental cycle • After we exchange the edges, the fundamental cycles of this tree would change • We need to modify the fundamental cycles e1 e1 e1 e2 e2 e2 f f f e3 e3 e3
Modify the fundamental cycle • Author uses the data structure C to maintain the fundamental cycles • C maintains the fundamental cycles corresponding to the current tree • There are 3 operations to construct computation tree: • After deleting edge ei in AG, merge the fundamental cycles contain ei • After contracting edge e in AG, contract edge e in C • Delete the nontree edge for the last son
Merge the fundamental cycles • Use 4 pointer to modify the cycles • This operation takes time proportional to the size of resulting cycle
Contract edge in C • This operation takes time proportional to fundamental cycles containing the contracted edge
Delete the nontree edge in C • If the nontree edge is a part of a multiedge, then do nothing • else delete the fundamental cycle containing the nontree edge • This operation takes time proportional to the size of its fundamental cycle
AG and C • When some edge e is added to set IN: • Contract e in AG and C • When some edge e is added to set OUT: • Delete e in AG and C • Merge the fundamental cycles containing e
Lemma 1.2 • The algorithm done at each node A of C(G)is O(|s(A)|+|g(A)|) • Where s(A) is the set of sons of A in C(G), g(A) is the set of sons in C’(G) of nodes in s(A)
Proof • When replace tree edge ei by f , We need to • Contract f in AG: constant time • merge fundamental cycles in C containing ei:it takes time proportional to the sum size of resulting cycle ( O(|g(A)|) ) • Contract ei in C: it takes time proportional to the number of cycles contain ei ( O(|g(A)|) ) • Contract eiin AG: it takes time proportional to the number of multiedges incident to the endpoints of ei( O(|g(A)|) )
Proof • Before operating the node is the last son, then • Delete f in AG: constant time • Delete f in C: time proportional to the size of its fundamental cycle( O(s(A)) ) • Every node takes O(|s(A)|+|g(A)|) time
Theorem 1.3 • All spanning trees can be correctly generated in O( N + V + E ) time by Algorithm 1 • [Proof] • First, construct a spanning tree and setup it’s data structure • require O( V + E ) time • Every node in computation tree C(G) takes O(|s(A)|+|g(A)|) time • Summing overall nodes of C(G) is O(N)
Theorem 1.4 • The space requirement of the spanning tree enumeration Algorithm 1 is O( V2E ) • [Proof] • At each node of C(G), take O( VE ) space • The height of C’(G) is at most V … … …