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General Physics 101 PHYS

General Physics 101 PHYS. Dr. Zyad Ahmed Tawfik. Email : zmohammed@inaya.edu.sa. Website : zyadinaya.wordpress.com. Lecture No. 7 Review and resolve quizzes on work and energy. Calculate work done on an object. 1- With out angle.

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General Physics 101 PHYS

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  1. General Physics101 PHYS Dr. Zyad Ahmed Tawfik Email : zmohammed@inaya.edu.sa Website : zyadinaya.wordpress.com

  2. Lecture No. 7 Review and resolve quizzes on work and energy

  3. Calculate work done on an object

  4. 1- With out angle • In this case it means that F and x MUST be parallel. To ensure that they are parallel we add the cosine on the end. Apply FORCE Displacement

  5. 1- With out angle • In this case it means that F and x MUST be parallel. To ensure that they are parallel we add the cosine on the end. Apply FORCE Displacement So the equation used to calculate the work(W) in this case it: W= F . d

  6. The equation used to calculate the work(W) in this case it: • W= Ff . d • This signal(-) Because in this case the friction force in the opposite direction for displacement • Also with friction force Friction FORCE Displacement

  7. With angle So in this case, the work done given by W = F . d cos q

  8. 3- Kinetic Energy and Work Vectors

  9. What is KineticEnergy? • Kinetic Energy is the energy of a particle due to its motion K = ½ mv2 (1) • K is the kinetic energy • m is the mass of the particle • v is the speed of the particle

  10. Work and Kinetic Energy • Also from equation (1) we can Wright • W = Kf-K0_______(2) • The equation (3) say • (total work done= The final kinetic energy of an object - initial kinetic energy) • _____________________________________________ • But the equation 2 can be written in this format W =½ mvf2 - ½ m v02 -------------------- (3) where k= ½ m v2 But DK = ½ mvf2 - ½ mvo2 so w= DK ---------(5) The equation (5) say “the net WORK done on an object is equal to the change in kinetic energy of the object."

  11. 4- Potential Energy Vectors

  12. Potential Energy • potential energy is energy stored in an object. • This energy has the potential to do work. • Gravity gives potential energy to an object. • This potential energy is a result of gravity pulling downwards. • Potential Energy means the work done by gravity on the object. • The formula for potential energy (U) due to gravity is U = m.g.h • P.E. = mass x height x gravity

  13. Potential Energy and Kinetic energy • Total mechanical energy = kinetic energy + potential energy E = K + u

  14. 6- Power The Laws of Motion

  15. Power • One useful application of Energy is to determine the RATE at which we store or use it. We call this application POWER! • Power is the time rate of energy transfer. • The Power is given by W F . d P = = t t • Units of Power • Where the unit of work(W) is joule and unit of time(t) is second. So The unit of power is a Watt where 1 watt = 1 joule / second

  16. also since, = = = h =d and F = mg W F . h m.g.h P t t t

  17. Quiz • Find the potential energy of 20 Kg mass child sitting on a roof 10m above the ground? • A truck is pulling a box of 20 Kg mass on a horizontal surface, a distance of 10 m with a constant speed. The force of friction between the box and the surface is 20 N. • - Find the work it did against the force of friction. • 3. A ball of 3 Kg mass was dropped from rest the top of tower • 50 m high. • - Find the speed of the ball 20 m above the base of the tower. • 4. A car of 800 Kg mass is travelling at 20 m/s speed coasts to a stop in 400 m on a rough horizontal road. • - Find the energy loss.

  18. 5. A woman of 50 Kg mass climb s a mountain 4000 m high. a) . Find the work she did against gravitational forces b). A Kilogram of fat supplies energy of 3.7x10^7 J. If she converts fat to energy with efficiency rate of 25%. How much fat he consumed in the climb. 6. A boy of 50 Kg mass climb’s a wall 500 m high. a) Find the work he did against gravitational forces. b) A Kilogram of fat supplies energy of 3.7x10^7 J. If he converts fat to energy with efficiency rate of 25%. How much fat he consumed in the climb. 7. A car of 800 Kg mass is travelling at 20 m/s speed coasts to a stop in 400 m on a rough horizontal road. - Find the force of friction.

  19. 8. A car of 800 Kg mass is travelling at 20 m/s speed hits a • concrete wall and comes to rest after smashing 1.5 meter • of the front of the car. • - Find the reactive force acting on the car body during the • crash. • A man raises a 10 Kg mass vertically upwards a distance of 0.5 m. He practices that 1000 times. • a) Find the work he did against gravitational forces. • b) A Kilogram of fat supplies energy of 3.7x10^7 J. If the • man converts fat to energy with efficiency rate of • 25%. How much fat he consumed in the exercise

  20. 10. A child of 30kg mass is running with speed 5m/s on a rough horizontal floor skids a distance 3 m till stopped . -Find the force of friction? 11. A child 0f 25 kg mass climbs a tower 50m height above the ground. Find his potential energy at the top of the tower ? 12. A car of 100 Kg mass is travelling at 15 m/s, speed hits a concrete wall and comes to rest after smashing 1.5 meter of the front of the car. a) Find the kinetic energy of the car b) Find the reactive force acting on the car body during the crash.

  21. Thank You for your Attention

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