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Chapter 1 Answers

Chapter 1 Answers. #8 3.05mL the 2.87mL grad cyl measurement limits precision #28 examples of matter/mixtures and phys/chem change #32 sig figs 1,2,3,3,2,3,3,4 #33 rounding 0.000342, 10340, 17.992, 337000 #37 188.1, 12, 4x10 -7 , 6.3x10 -25 , 4.90 , 0.22%

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Chapter 1 Answers

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  1. Chapter 1 Answers #8 3.05mL the 2.87mL grad cyl measurement limits precision #28 examples of matter/mixtures and phys/chem change #32 sig figs 1,2,3,3,2,3,3,4 #33 rounding 0.000342, 10340, 17.992, 337000 #37 188.1, 12, 4x10-7 , 6.3x10-25 , 4.90 , 0.22% #73 gaseous element, mixture gases, mixture gases, gaseous compound, solid, mixture gaseous elements #74 know the definitions #77 sub C, mix, mix, sub E, mix, sub E, mix, mix, sub C #94 no chance of success, 19.3kg ~42lbs catch not plausible #116 V=r2h, assume linear density change and know to extrapolate

  2. Chapter 2 answers #5 d) cannot tell without chemical ID #14 b) and c) #21 JJThomson - negatively (-) charged particle Rutherford - dense (+) charge nucleus, atom mostly empty space #33 88.0g - simply conservation of mass #50 17 Cl halogen, Be alkaline metal, Eu lanthanide metal #74 Naming - Need to memorize Table 2.5, then use analogies of the same group… I is a halogen, so same as Cl thusClO31- chlorate ion then IO31- iodate ion Again - like HClO HIO would be hypoiodous acid

  3. Chapter 3 answers #30 Reactant in excess (more than enough to react with other reactant(s) , limiting reactant limits reaction (all used up), excess reactant have no effect on final product amounts #34 abundance x mass for each isotope and total all isotopes atomic mass 47.89 is titanium #68 Y 13.35%, Ba 41.22%, Cu 28.62%, O 16.81% #76 SNH 47.1amu 4 units S4N4H4 , NPCl2 115.9amu 3 units N3P3Cl6 , CoC4O4 170.9amu 2 units Co2C8O8 , SN 46.1amu 4 units S4N4 #82 mole ratio PNCl2 115.9 amu thus 5 units P5N5Cl10 molecular formula #90 3Pb(NO3)2 (aq) + 2Na3PO4 (aq) --> 2Pb3(PO4)2 (s) + 6NaNO3 (aq) Sr(OH)2 (aq)+ 2HBr (aq) --> 2H2O(l) + SrBr2 (aq)

  4. Chpt 3 answers - con’t #99 21.5g iron oxide, 7.25g Al, produce 13.7g aluminum oxide #114 do not know but 1170g is theoretical yield, chlorobenzene is excess, 3.57moles or 401g chlorobenzene left over, 17.1% yield #127 0.301g H2O2 should result HCl is excess and 0.036g remain 2 sig figs because when you subtract to get amount excess the diff is small. #158 what is the reaction? We aren’t sure… but we calculate the amount of H that reacts from H2 gas info - .0745mol H2 means .149 mol H and 0.149 mol Cl, 2.25g Sc is 0.05 mol so Cl is 3x Sc Thus ScCl3 #159 7.68cm3/board, 8.96g/cm3,10000 boards, 80% removed = 551,000g Cu = 8660 moles Cu -> 590000 g NH3 & 1,750000g other #168 mole ratios C 3.67, N 1, H 5.66, O 2.66 x3!!! C11N3H17O8 MW=319 165lb=75kg LD50=750g 750x10-6g 2.35x10-6moles tetro 1.4x1018units #172 i) cannot determine depends on how much greater A is than B ii) B is limiting because will have fewer moles and always need 5times b) B must be O2 if H2 then too much mass for A (>44) c) C3H8 44g/mol same as CO2

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