1 / 7

ATF2 Beam Size Correction by Linear Knob

ATF2 Beam Size Correction by Linear Knob. Making Linear Knob Mover of SX DX WaistX, WaistY, PEX DY PEY, Coupling R1 is used for the coupling index. Orthogonal Knob WaistX: SF1_DX=-0.00043123 wx SD4_DX=0.00256159 wx SF6_DX=-0.0167073 wx

helia
Télécharger la présentation

ATF2 Beam Size Correction by Linear Knob

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ATF2 Beam Size Correction by Linear Knob Making Linear Knob Mover of SX DXWaistX, WaistY, PEX DYPEY, Coupling R1 is used for the coupling index Orthogonal Knob WaistX: SF1_DX=-0.00043123 wx SD4_DX=0.00256159 wx SF6_DX=-0.0167073 wx WaistY: SF1_DX=-0.0121574 wy SD4_DX= 0.0721866 wy SF6_DX= -0.0243731 wy PEX: SF1_DX= 0.00539274 px SD4_DX= -0.000363894 px SF6_DX= 0.0122067 px PEY: SD4_DY= -0.279389 py SD0_DY= 0.353846 py R1: SD4_DY= -0.0584437 r1 SD0_DY= -0.0479828 r1 Response of Each Knob

  2. Misalignment of Q DX Q dx is distributed according to Gaussian distribution. WaistY correction is done for sy. Correction step:1mm(sy>1mm) 100mm(sy>100nm) 20mm(sy<100nm) because of the resolution of the sy calculation by tracking(NP=1000) Before Cor. After Cor. dx=5e-5m  dx=4e-5m  95% CL values are plotted.

  3. Misalignment of Q DY Q dy is distributed according to Gaussian distribution. R1,WaistY,PEY correction is done for sy in this order. Correction step:R1:1e-3 (sy>1mm) 1e-4(sy>100nm) 1e-5(sy<100nm) PEY: 10mm Example:dy=1e-5m  sy=60.5nm(95%CL) after correction Correction is not good enough

  4. Redefinition of Linear Knob Vertical Beam Size with Coupling Redefinition of Knob PEY: SF6_DY= -0.231976 py SD4_DY= -0.186651 py SD0_DY= 0.429982 py R1: SF6_DY= 0.526463 r1 SD4_DY= -0.268909 r1 SD0_DY= -0.220771 r1 R2: SF6_DY= 0.387005 r1 SD4_DY= -0.154714 r1 SD0_DY= -0.127017 r1 Need for correction not only r1 but also r2 Response for R2 Correction gu=261,bu=0.004  r2 correction is important Order: R2,R1,WY,PEY Step: R1:1e-2 (sy>1mm) 1e-3(sy>100nm) 1e-4(sy<100nm) R2:1e-3 (sy>1mm) 1e-4(sy>100nm) 2e-5(sy<100nm) Performance Example:After correction for dy=1e-5 95%CL value 60.5nm  47.3nm  New Knob Old Knob

  5. Misalignment of Q DY revised Misalignment of Q roll Iterative correction works well for the event that the 1st correction failed. e.g.) roll=1e-4 after one cor. sy=65.6nmcor. again sy=36.6nm 

  6. # of iteration = 2 For only Q-dx error, iteration has no meaning because the correction is for WaistY only. Iterative Correction Misalignment of Q roll Misalignment of Q dy Field Error of Q dK1 Only WaistY correction No iteration

  7. Errors (dK1/K1, dx, dy, roll)=a(5e-4, 40mm, 20mm,100mrad) sy Correction with All Errors of Q Correction # of iteration ≤ 5 Iteration stops if sy≤ 35nm For a<0.7, sy<40nm after correction Mover Spec. Requirement Minimum step min. coeff. knob min.step WY:2e-5 SF1_DX=-0.0121574 wy 2.4e-7 PEY:1e-5 SD4_DY= -0.186651 py 1.9e-6 R1:1e-4 SD0_DY= -0.220771 r1 2.2e-5 R2:2e-5 SD0_DY= -0.127017 r1 2.5e-6 Dynamic range For a=0.6 max. coeff. knob min.step maxWY:1.98e-3 SD4_DX= 0.0721866 wy 1.4e-4 maxPEY:3e-4 SD0_DY= 0.429982 py 1.3e-4 maxR1:1.3e-3 SF6_DY= 0.526463 r1 6.5e-4 maxR2:3.8e-3 SF6_DY= 0.387005 r1 1.5e-3

More Related