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Kuat geser Beton ( Vn )

Kuat geser Beton ( Vn ). 600 mm ( d ). 2 8. 600 mm ( d ). 300 mm ( bw ). s. d. d. 2 8. fy = 414 N / mm ² fc’ = 27,5 N / mm ². 300mm. Tahanan geser max yg bisa ditahan beton

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Kuat geser Beton ( Vn )

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  1. Kuat geser Beton ( Vn ) 600 mm ( d ) 28 600 mm ( d ) 300 mm ( bw ) s d d 28 fy = 414 N / mm² fc’ = 27,5 N / mm² 300mm Tahanan geser max yg bisa ditahan beton c = fc’ / 6 N / mm²=  27,5 / 6 =0.87N/ mm² . Kuat geser max yg bisa ditahan beton ( V c )=(  c ) x bw x d Vc =0.87 x 600 x 300 =156600 N As=luas pot tulangan begel s=jarak begel /sengkang d = tinggi balok fy =kekuatan baja per mm² Kuat geser max yg bisa ditahan 2 tul. baja  8 mm tegak( satu.begel) Vb =As x fy = 2 x ¼  8² x 414 = 41598,72 Newton Jumlah begel selebar bid geser = nb =d/s batang Kuat geser max yg bisa ditahan tul. baja ( begel/sengkang ) ,selebar bidang geser ( V s ) = Vb x nb = As x fy x d/s s = V s / (As x fy x d)

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