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This chapter on Rotational Motion, authored by Dr. Larry Dennis from FSU's Department of Physics, explores essential principles including rolling without slipping, torque, rotational energy, and conservation of angular momentum. Key equations such as (tau = Ialpha) and (K = frac{1}{2}Iomega^2) are presented alongside practical examples, like calculating the torque needed to accelerate a merry-go-round. The concepts are vital for understanding the mechanics behind rotating systems and are supported with illustrative problems for enhanced comprehension.
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Physics 2053C – Fall 2001 Chapter 8 Rotational Motion Dr. Larry Dennis, FSU Department of Physics
Rotational Motion • Uses all the above concepts and, • Rolling without slipping. • v = x/t • a = v/t • When a = constant: • v = vo + at • x = xo + vot + ½at2 • = /t • = /t • When = constant: • = o + t • = o + ot + ½t2
F1 F2 R1 R2 Rotational Forces Torque • = I = RFsin or RF
Rotational Energy & Momentum • Kinetic Energy: K = ½I2 • Rotational energy is often conserved. • Rotational energy must be included in total energy. • Angular Momentum: L = I • Angular momentum is conserved.
R M M2 R2 R1 M1 Moments of Inertia I = MR2 I = M1R12 + M2R22
Moments of Inertia Hollow Disk I = MR2 Solid Disk I = ½MR2 Solid Sphere I = 2/5MR2
Conservation of Angular Momentum Change in angular momentum = Torque If then the angular momentum remains constant. (I)before=(I)after
Conservation of Angular Momentum • Examples: • Figure Skater • Diver • Gymnast
CAPA 9 & 10 • A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. • Calculate the torque required to produce the acceleration, neglecting any frictional torque. • What is the force required? = I
CAPA 9 & 10 • A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. • Calculate the torque required to produce the acceleration, neglecting any frictional torque. • What is the force required? I = 2*McRc2 + ½MdRd2 I = (2*Mc +½Md )R2
CAPA 9 & 10 • A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. I = (2*Mc +½Md )Rc2 I = (2*25+½*750)2.72 I = 3098 kg*m2
CAPA 9 & 10 A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. 8. Calculate the torque required to produce the acceleration, neglecting any frictional torque. = I = /t = 18 rpm*1/60 min/s * 2 rad/s /9 s = 0.209 rad/s2
CAPA 9 & 10 A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. 8. Calculate the torque required to produce the acceleration, neglecting any frictional torque. = I = 3098 kg*m2 *0.209 rad/s2 = 649 kg*m2/s2 = 649 N-m
F R CAPA 9 & 10 A day-care worker pushes tangentially on a hand-driven merry-go-round and is able to accelerate it from rest to a spinning rate of 18.0 rpm in 9 seconds. Assume the merry-go-round is a disk of radius 2.7 m and has a mass of 750 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. 9. What is the force required? = FR sin F = /Rsin = 649 N-m/( 2.7 m * 1 ) F = 240 N
CAPA 11 & 12 (I)initial=(I)final Iii=Iff f=Iii /If
CAPA 12 (½I2)initialand(½I2)final are not the same. ½Iii2<½Iff2
Quiz #5 – Chapter 8 Sample Questions: Chap. 8: 2, 8, 12 Sample Problems: Chap. 8: 17, 43, 66 Answers to 66: A) 1.19 rad/s B) Before = 2000 J After = 1190 J
Next Time • Quiz on Chapter 8 • Begin Chapter 9 • Please see me with any questions or comments. See you on Wednesday.