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Chapter 13

Chapter 13. Vibrations and Waves. Hooke’s Law 13.1. F s = - k x F s is the spring force k is the spring constant It is a measure of the stiffness of the spring A large k indicates a stiff spring and a small k indicates a soft spring

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Chapter 13

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  1. Chapter 13 Vibrations and Waves

  2. Hooke’s Law 13.1 • Fs = - k x • Fs is the spring force • k is the spring constant • It is a measure of the stiffness of the spring • A large k indicates a stiff spring and a small k indicates a soft spring • x is the displacement of the object from its equilibrium position • x = 0 at the equilibrium position • The negative sign indicates that the force is always directed opposite to the displacement

  3. Hooke’s Law Force • The force always acts toward the equilibrium position • It is called the restoring force • The direction of the restoring force is such that the object is being either pushed or pulled toward the equilibrium position

  4. Hooke’s Law Applied to a Spring – Mass System (concept) • When x is positive (to the right), F is negative (to the left) • When x = 0 (at equilibrium), F is 0 • When x is negative (to the left), F is positive (to the right)

  5. Motion of the Spring-Mass System • Assume the object is initially pulled to a distance A and released from rest • As the object moves toward the equilibrium position, F and a decrease, but v increases • At x = 0, F and a are zero, but v is a maximum • The object’s momentum causes it to overshoot the equilibrium position

  6. Motion of the Spring-Mass System, cont • The force and acceleration start to increase in the opposite direction and velocity decreases • The motion momentarily comes to a stop at x = - A • It then accelerates back toward the equilibrium position • The motion continues indefinitely

  7. Simple Harmonic Motion • Motion that occurs when the net force along the direction of motion obeys Hooke’s Law • The force is proportional to the displacementand always directed toward the equilibrium position • The motion of a spring mass system is an example of Simple Harmonic Motion

  8. Simple Harmonic Motion, cont. • Not all periodic motion over the same path can be considered Simple Harmonic motion • To be Simple Harmonic motion, the force needs to obey Hooke’s Law

  9. Amplitude • Amplitude, A • The amplitude is the maximum position of the object relative to the equilibrium position • In the absence of friction, an object in simple harmonic motion will oscillate between the positions x = ±A

  10. Period and Frequency • The period, T, is the time that it takes for the object to complete one complete cycle of motion • From x = A to x = - A and back to x = A • The frequency, ƒ, is the number of complete cycles or vibrations per unit time • ƒ = 1 / T • Frequency is the reciprocal of the period

  11. Acceleration of an Object in Simple Harmonic Motion • Newton’s second law will relate force and acceleration • The force is given by Hooke’s Law • F = - k x = m a • a = -kx / m • The acceleration is a function of position • Acceleration is not constant and therefore the uniformly accelerated motion equation cannot be applied

  12. Fig. 13-2, p.326

  13. QQ 13.1 • A block on the end of a spring is pulled to position x =A and released. Through what total distance does it travel in one full cycle of its motion? • (a) A/2 (b) A (c) 2A (d) 4A

  14. QQ 13.1 • A block on the end of a spring is pulled to position x =A and released. Through what total distance does it travel in one full cycle of its motion? • (a) A/2 (b) A (c) 2A (d) 4A

  15. QQ 13.2 • For a simple harmonic oscillator, which of the following pairs of vector quantities can’t both point in the same direction? (The position vector is the displacement from equilibrium.) • (a) position and velocity • (b) velocity and acceleration • (c) position and acceleration

  16. QQ 13.2 • For a simple harmonic oscillator, which of the following pairs of vector quantities can’t both point in the same direction? (The position vector is the displacement from equilibrium.) • (a) position and velocity • (b) velocity and acceleration • (c) position and acceleration

  17. Example 13.2 • Problem A 0.350-kg object attached to a spring of force constant 1.30x102 N/m is free to move on a frictionless horizontal surface, as in Active Figure 13.1. If the object is released from rest at x=0.100 m, find the force on it and its acceleration at x=0.100 m, x=0.050 0 m, x=0 m, x=0.050 0 m, and x=0.100 m.

  18. Fig. 13-1, p.425

  19. Example 13.2 cont • Solution • Write Hooke’s force law: Fs=-kx • Substitute the value for k, and take x=A=0.100 m, • finding the force at that point: • Fmax=-kA (1.30x102 N/m)(0.100 m) • =-13.0 N • Solve Newton’s second law for a and substitute to find • the acceleration at x=A: • ma=Fmax

  20. Example 13.2 cont

  21. Elastic Potential Energy 13.2 • A compressed spring has potential energy • The compressed spring, when allowed to expand, can apply a force to an object • The potential energy of the spring can be transformed into kinetic energy of the object

  22. Elastic Potential Energy, cont • The energy stored in a stretched or compressed spring or other elastic material is called elastic potential energy • PEs = ½kx2 • The energy is stored only when the spring is stretched or compressed • Elastic potential energy can be added to the statements of Conservation of Energy and Work-Energy

  23. Fig. 13-3, p.428

  24. Energy in a Spring Mass System • A block sliding on a frictionless system collides with a light spring • The block attaches to the spring • The system oscillates in Simple Harmonic Motion

  25. Energy Transformations (concept) • The block is moving on a frictionless surface • The total mechanical energy of the system is the kinetic energy of the block

  26. Energy Transformations, 2 (concept) • The spring is partially compressed • The energy is shared between kinetic energy and elastic potential energy • The total mechanical energy is the sum of the kinetic energy and the elastic potential energy

  27. Energy Transformations, 3 (concept) • The spring is now fully compressed • The block momentarily stops • The total mechanical energy is stored as elastic potential energy of the spring

  28. Energy Transformations, 4 (concept) • When the block leaves the spring, the total mechanical energy is in the kinetic energy of the block • The spring force is conservative and the total energy of the system remains constant

  29. Velocity as a Function of Position • Conservation of Energy allows a calculation of the velocity of the object at any position in its motion • Speed is a maximum at x = 0 • Speed is zero at x = ±A • The ± indicates the object can be traveling in either direction

  30. Fig. 13-5, p.429

  31. Simple Harmonic Motion and Uniform Circular Motion 13.3 • A ball is attached to the rim of a turntable of radius A • The focus is on the shadow that the ball casts on the screen • When the turntable rotates with a constant angular speed, the shadow moves in simple harmonic motion

  32. Period and Frequency from Circular Motion • Period • This gives the time required for an object of mass m attached to a spring of constant k to complete one cycle of its motion • Frequency • Units are cycles/second or Hertz, Hz

  33. Angular Frequency • The angular frequency is related to the frequency • The frequency gives the number of cycles per second • The angular frequency gives the number of radians (rotations) per second

  34. Effective Spring Mass • A graph of T2 versus m does not pass through the origin • The spring has mass and oscillates • For a cylindrical spring, the effective additional mass of a light spring is 1/3 the mass of the spring

  35. QQ 13.4 • An object of mass m is attached to a horizontal spring, stretched to a displacement A from equilibrium and released, undergoing harmonic oscillations on a frictionless surface with period T0. The experiment is then repeated with a mass of 4m. • What’s the new period of oscillation? • (a) 2T0 (b) T0 (c) T0/2 (d) T0/4.

  36. QQ 13.4 • An object of mass m is attached to a horizontal spring, stretched to a displacement A from equilibrium and released, undergoing harmonic oscillations on a frictionless surface with period T0. The experiment is then repeated with a mass of 4m. • What’s the new period of oscillation? • (a) 2T0 (b) T0 (c) T0/2 (d) T0/4.

  37. Motion as a Function of Time 13.4 • Use of a reference circle allows a description of the motion • x = A cos (2pƒt) • x is the position at time t • x varies between +A and -A

  38. Graphical Representation of Motion (concept) • When x is a maximum or minimum, velocity is zero • When x is zero, the velocity is a maximum • When x is a maximum in the positive direction, a is a maximum in the negative direction

  39. Motion Equations • Remember, the uniformly accelerated motion equations cannot be used • x = A cos (2pƒt) = A cos wt • v = -2pƒA sin (2pƒt) = -A w sin wt • a = -4p2ƒ2A cos (2pƒt) = -Aw2 cos wt

  40. Verification of Sinusoidal Nature • This experiment shows the sinusoidal nature of simple harmonic motion • The spring mass system oscillates in simple harmonic motion • The attached pen traces out the sinusoidal motion

  41. QQ 13.6 • If the amplitude of a system moving in simple harmonic motion is doubled, which of the following quantities doesn’t change? • (a) total energy, • (b) maximum speed, • (c) maximum acceleration, • (d) period.

  42. QQ 13.6 • If the amplitude of a system moving in simple harmonic motion is doubled, which of the following quantities doesn’t change? • (a) total energy, • (b) maximum speed, • (c) maximum acceleration, • (d) period.

  43. Simple Pendulum 13.5 • The simple pendulum is another example of simple harmonic motion • The force is the component of the weight tangentto the path of motion • Ft = - m g sin θ

  44. Simple Pendulum, cont • In general, the motion of a pendulum is not simple harmonic • However, for small angles, it becomes simple harmonic • In general, angles < 15° are small enough • sin θ = θ • Ft = - m g θ • This force obeys Hooke’s Law

  45. Period of Simple Pendulum • This shows that the period is independent of the amplitude • The period depends on the length of the pendulum and the acceleration of gravity at the location of the pendulum

  46. Simple Pendulum Compared to a Spring-Mass System

  47. QQ 13.7 • A simple pendulum is suspended from the ceiling of a stationary elevator, and the period is measured. If the elevator moves with constant velocity, does the period • (a) increase, • (b) decrease, or • (c) remain the same? • If the elevator accelerates upward, does the period: • (a) increase, (b) decrease, or (c) remain the same?

  48. QQ 13.7 • A simple pendulum is suspended from the ceiling of a stationary elevator, and the period is measured. If the elevator moves with constant velocity, does the period • (a) increase, • (b) decrease, or • (c) remain the same? • If the elevator accelerates upward, does the period: • (a) increase, (b) decrease, or (c) remain the same?

  49. QQ 13.8 • A pendulum clock depends on the period of a pendulum to keep correct time. Suppose a pendulum clock is keeping correct time and then Dennis the Menace slides the bob of the pendulum downward on the oscillating rod. Does the clock run • (a) slow, (b) fast, or (c) correctly?

  50. QQ 13.8 • A pendulum clock depends on the period of a pendulum to keep correct time. Suppose a pendulum clock is keeping correct time and then Dennis the Menace slides the bob of the pendulum downward on the oscillating rod. Does the clock run • (a) slow, (b) fast, or (c) correctly?

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