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Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m PowerPoint Presentation
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Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m

Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m

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Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m 2 x 3,5 m = 140 kg/m

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  1. Modul 4 LENDUTAN PADA GORDING q angin = q2 = W angin x j = 40 kg/m2 x 3,5 m = 140 kg/m q2 x 1 cos 2 140 kg / m 2 x 1 m cos 30,9637 o P angin = Pa2 = = = 163,26 kg 1 4 M angin = Ma2 = = x Pa2 x j x 163,26 kg x 3,5 m 1 4 = 142,85 kgm 1 http://www.mercubuana.ac.id

  2. 25,67243,522 = 5 4 = 50,52 kg/cm2 < (lt x ) 5 4 50,52 kg/cm2 < ( 100 kg/cm2 x = ) = 50,52 kg/cm2 < 125 kg/cm2 ........................ (OK) 3,5 x 100 300 L 300 Lendutan ijin = = = 1,16 cm BENTUK 1 1) Beban mati : = 99,3 kg/m’ q bm q bm x = 99,3 kg/m x sin 54,4623o = 80,8 kg/m q bm y = 99,3 kg/m x cos 54,4623o = 57,72 kg/m 2) Beban angin: 40 kg / m 2 x 1 m cos 54,4623o 40 kg / m 0,5812 qa = = = 68,82 kg/m’ qax = 0 qay = 68,82 kg/m’ 3) Total beban terbagi rata: qx = q bmx + q ax = 80,8 kg/m + 0 = 80,8 kg/m qy = q bmy + q ay = 57,72 kg/m + 68,82 kg/m = 126,54 kg/m 3 http://www.mercubuana.ac.id

  3. q x L4 x x EI y P x L3 x x EI y 5 384 1 48 x = + 80,8 / 100 x 350 4 1 100.000 x x 20 x 12 3 12 81,37 x 350 3 1 100.000 x x 20 x 12 3 12 5 384 1 48 x x = + = 0,55 + 0,25 = 0,80 cm q y x L4 EI x Py x L3 EI x 5 384 1 48 y = x x + 126,54 / 100 x 350 4 1 100.000 x x 12 x 20 3 12 58,12 x 350 3 1 100.000 x x 12 x 20 3 12 5 384 1 48 x x = + = 0,31 + 0,06 = 0,37 cm x2y2 0,8020,372  = = = 0,88 cm < = 1,16 cm ....... (OK) Jadi gording dengan ukuran penampang 12/20 dapat dipakai LENDUTAN PADA GORDING () 3,5 x 100 300 L 300 Lendutan ijin = = = 1,16 cm BENTUK 2 1) Beban mati : = 99,3 kg/m’ q bm q bm x = 99,3 kg/m x sin 30,9637o = 51,08 kg/m q bm y = 99,3 kg/m x cos 30,9637o = 85,14 kg/m 2) Beban angin: 5 http://www.mercubuana.ac.id