1 / 21

Genome closure and finishing

Genome closure and finishing. Clone walking. clone insert (from shotgun library). primer locations. Already sequenced. Unsequenced. sequencing primer. direction of extension. tgcatgatcgtgatcat acgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct. PCR to close gaps. Scaffold.

lyle
Télécharger la présentation

Genome closure and finishing

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Genome closure and finishing

  2. Clone walking clone insert (from shotgun library) primer locations Already sequenced Unsequenced sequencing primer direction of extension tgcatgatcgtgatcat acgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct...

  3. PCR to close gaps Scaffold Design primers at these locations • Run PCR for each pair of primers • Primers must be in non-repeat sequences • Primers must be as close as possible to each gap • PCR works best if primers are less than 2kb apart

  4. What about physical gaps? How to order and orient all scaffolds?

  5. Traditional strategy: combinatorial PCR • Design primers for each end of each scaffold • With N/2 scaffolds and N “ends”, run a separate PCR reaction for every pair of ends • (N choose 2) reactions = N(N-1)/2 • Example: 24 physical gaps, 48 ends, PCR experiments will be:

  6. Multiplex PCR actgagatatac gttgagatataa gcgacgctgctc ccagcgctgttc

  7. Multiplexing more primers • Up to 12 primers per tube • If any two primers surround the same gap, they produce a product • If more than 2 pairs react, we get multiple products • Let N = number of primers = 48 • K = max primers/tube = 12

  8. POMP:pipette optimized multiplex PCR • minimize number of laboratory reactions • with N=48, number of combinatorial PCRs is 1128 • number of pipettings = 2256 • POMP: 28 reactions, 104 pipettings

  9. POMP • Create pools of size K/2 = 6 • Each of N=48 primers put into 1 pool • So we create N/(K/2) = 8 pools, P1...P8 • Now create multiplex PCR reactions with all pairs of pools • (8 choose 2) = 28 reactions needed

  10. POMP • Guarantees that all primers are tested against all others • Each reaction tests (12 choose 2) = 66 pairs • Protocol tests 66*28 = 1848 pairs • Only 1128 distinct pairs, so POMP has some redundancy - some pairs appear in more than one reaction

  11. Pooling primers ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT ACGTCGATGCATCGA GCATGCTCGTACGAT ATCGTGACAGTGAAC GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT GCATCGATGCATGT

  12. Testing all Pools P1

  13. How many pipette operations? • 48 pipettings to create the pools (one for each primer) • 2 pipettings to create each multiplex reaction mix • Total: 48 + 2(28) = 104

  14. Results: Streptococcus pneumoniae • N=48 primers, N/2 = 24 scaffolds, 24 gaps • 19 products observed in the first experiment • Q: how many gaps closed?

  15. Interpreting results • Case 1: product appears with Pi and Pj, but not in any other lane containing Pi • see P2P6 or P7P8 on previous slide • purify and sequence product directly • Case 2: product appears in Pi and Pj and also in other lanes containing Pi • thus two primers within Pi reacted • see pool P5 on previous slide

  16. A: Deconvoluting pool P5: eliminate each of the six primers from the pool and run 6 standard PCRs Answer: p25 and p29

  17. B: Pools P2 and P3 gave two products • Could run 12 more PCRs: eliminate each of 12 primers and re-run multiplex PCR • However, 5 of the 12 were eliminated by other results • For example, primer p10 was eliminated by results from P1-P2 • Answers: • p11 in Pool 2 pairs with p13 in Pool 3 • p16 in Pool 3 pairs with p8 in Pool 2

  18. POMP requirements • (Ideally) If no restriction on K, choose K based on N (where N = 2 x (#gaps)) • Make pools of size K/2 Reactions: Pipettings:

  19. POMP summary for S. pneumoniae • Out of 48 gaps, 42 were closed • Strategy employs slightly under N/2 reactions, thus expected number of products per tube is ~1 • This was borne out in experiments • This became a standard lab technique at TIGR

More Related