1 / 7

Measuring moving charges

Measuring moving charges. Voltmeter. Measures potential difference (voltage), the energy of each charge Connects to either side of a load. Ammeter. Measures current, how many charges move past a point in a given time. Connected into a circuit between two parts. Ohm’s Law.

maili
Télécharger la présentation

Measuring moving charges

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Measuring moving charges

  2. Voltmeter • Measures potential difference (voltage), the energy of each charge • Connects to either side of a load

  3. Ammeter • Measures current, how many charges move past a point in a given time. • Connected into a circuit between two parts

  4. Ohm’s Law • George Ohm discovered a relationship between voltage and current. • If you increase the voltage to a load, current will increase • If you keep same voltage but increase the load, current will decrease

  5. Ohm’s Law • The equation for this relationship is: V = IR Where: V - voltage (measured in volts, V) I - current (measured in amps, A) R - resistance (measured in ohms, Ω)

  6. Solving Science Problems Involving Equations • Given : record all given quantities • Unknown : identify what value you are looking for. • Equation : write the equation you are going to use. • Solution : Substitute values into the equation and calculate the answer (include the correct units). • Statement : write an answer statement in sentence form.

  7. Example: • The current required to operate an electric can opener is 1.5A. What is the resistance of the can opener if the voltage supplied is 120V? Given:Equation:Solution : Unknown: Statement : 120 V = R 1.5 A V=120V V=IR I=1.5A V=IR I I 80Ω= R R=? V=R I Therefore the resistance of the can opener is 80 Ω.

More Related