Biological systems are open

1. Develop our understanding of the utility of G • Introduce thermodynamic equilibrium (helps us to determine G°´) • Effect of T on thermodynamic equilibrium Biological systems are open

8. We need to handle systems that contain more than one component, the concentrations of which can vary (e.g. a solution containing a number of dissolved reactants). These are called open systems. Consider: A + B <===> C + D Thermodynamics of open systems (reaction mixes) There are four solutes (reactants or products) and the concentrations of A, B, C and D are affected by this and other reactions. How do we calculate G for this reaction?

9. For one component (A): GA = GA°´ + nART.ln[A] And for 1 mole of A: where the units are free energy per mole (J mol-1). This quantity is also known as the chemical potential (µA)and we write: µA = µA°´ + RT.ln[A] Previously we had for the general case: dG = Vdp - SdT For open, multicomponent systems, we write: dG = Vdp - SdT + iµidni Thermodynamics of open systems (reaction mixes)

10. In biological systems (constant p and T): dG = i µidni or G = i µini We can now calculate G for a specific reaction: aA + bB <===> cC + dD where the reactants are A and B, the products are C and D. a, b, c and d represent the number of moles of each that participate in the reaction. For this reaction: G = Gproducts - Greactants = (cµc + dµd) - (aµa + bµb) Thermodynamics of open systems (reaction mixes)

11. But µA = µA°´ + RT.ln[A] etc. so: G = [(cµc°´ + dµd°´) - (aµa°´ + bµb°´) + RTln([C]c[D]d/[A]a[B]b) which we express as: G = G°´ + RTln([C]c[D]d/[A]a[B]b) (Joules) To find the free energy change per mole, note that a, b, c and d will reflect the stoichiometry of the reaction (the numbers of each type of molecule involved in a single reaction). For example, a single reaction might involve the following numbers of molecules: 2A + 1B <----> 1C + 2D which is the same as: A + A + B <----> C + D + D Thermodynamics of open systems (reaction mixes)

12. We now have an equation which allows us to calculate G in practice: (J mol-1) a, b, c and d are the stoichiometric coefficients. G°´ is the standard free energy change per mole. Thermodynamics of open systems (reaction mixes) Standard free energy change per mole is the free energy change that occurs when reactants at 1 M are completely converted to products at 1 M at standard p, T and pH.

13. We calculate G so that we can determine the spontaneous direction of a reaction (favourable or unfavourable). To do that we must determine: • G°´ • the concentration of each component • the stoichiometry of the reaction. • We need G < 0 for a favourable forward reaction. We can drive the reaction forward either by: • increasing [A] and/or [B] • decreasing [C] and/or [D] • Living cells can (sometimes) control reactant/product concentrations to ensure that G < 0 for desired reactions. Thermodynamic equilibrium

14. In many cases there is a dynamic steady state: new reactants are made and products consumed in other reactions in order to keep concentrations steady. So G holds constant and, if it is negative, the reaction keeps going. If the cell dies, the reaction will reach thermodynamic equilibrium and come to a halt. Let’s see what happens: We have: If G < 0 at time zero and the system is isolated, then G becomes less negative as the concentrations of C and D build up (and those of A and B decline). Eventually equilibrium is reached when G =0. Thermodynamic equilibrium

15. At equilibrium, and define the equilibrium constant K: This constant depends on the chemical natures of the reactants and products. We measure G°´ by measuring the concentrations of A, B, C and D once the reaction has reached equilibrium. Thermodynamic equilibrium

16. Note: if G°´ < 0, then ([C][D])eq > ([A][B])eq (for a=b=c=d=1) if G°´ > 0, then ([C][D])eq < ([A][B])eq Thus, G°´ determines whether the reactants or products predominate at equilibrium. T Thermodynamic equilibrium is not a static state (conversion of A and B to C and D and back again keeps going but there is no net change in their concentrations). Thermodynamic equilibrium

17. We can write: G°´ = -RTlnK= H°´ - TS°´ Thus, The effect of temperature We can therefore plot lnK vs 1/T to determine H°´ and S°´, the standard enthalpy and entropy of the reaction respectively. Such a plot is known as a Van’t Hoff plot. It will give a straight-line if H°´ is independent of T (usually true for narrow ranges of T).

18. The sign of G tells us the spontaneous direction of a reaction:G < 0, forwardG > 0, reverseG = 0, equilibrium • G°´, the standard free energy change for a reaction determines the relative concentrations of reactants and products that will be found at thermodynamic equilibrium. (3) Neither quantity tells us about the rate of the reaction. Summary See a textbook for more details on G and G°´ - we will see this later on at transition state theory

19. References 1. Biological Physics. Energy, Information, Life Philip Nelson, (Freeman and Company, New York, 2004). 2. Principles of Physical Biochemistry, chapter 2, pp. 69-89 Kensal E. van Holde, W. Curtis Johnson and P. Shing Ho (Pretice Hall, Upper Saddle River, 1992).