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# Module 9001 Mass Balance

Download Presentation ## Module 9001 Mass Balance

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1. Module 9001Mass Balance Paul Ashall, 2008

2. The accounting of all mass in a chemical/pharmaceutical process is referred to as a mass (or material) balance. Paul Ashall, 2008

3. Uses • ‘day to day’ operation of process for monitoring operating efficiency • Making calculations for design and development of a process i.e. quantities required, sizing equipment, number of items of equipment Paul Ashall, 2008

4. Simple example – batch mixing process 200 kg of a 40% w/w methanol/water solution is mixed with 100 kg of a 70% w/w methanol/water solution in a batch mixer unit. What is the final quantity and composition? Paul Ashall, 2008

5. continued Total initial mass = total final mass = 300 kg Initial methanol mass = final methanol mass 80 + 70 = final methanol mass = 150 kg Therefore final composition of batch is (150/300) x 100 = 50 % by wt. Paul Ashall, 2008

6. Exercise 1000 kg of 8% by wt. sodium hydroxide (NaOH) solution is required. 20% sodium hydroxide solution in water and pure water are available. How much of each is required? Paul Ashall, 2008

7. Batch processes Batch processes operate to a batch cycle and are non-steady state. Materials are added to a vessel in one operation and then process is carried out and batch cycle repeated. Integral balances are carried out on batch processes where balances are carried out on the initial and final states of the system. Paul Ashall, 2008

8. Batch cycle • Sequence of operations/steps repeated according to a cycle • Batch cycle time • Batch size Paul Ashall, 2008

9. Simple batch reaction cycle 3 steps Add reactants etc reaction Empty reactor Next cycle Start cycle t=0 t, finish cycle Paul Ashall, 2008

10. Continuous processes These processes are continuous in nature and operate in steady state and balances are carried out over a fixed period of time. Materials enter and leave process continuously. Paul Ashall, 2008

11. Law of conservation of mass When there is no net accumulation or depletion of mass in a system (steady state) then: Total mass entering system = total mass leaving system or total mass at start = total final mass Paul Ashall, 2008

12. General mass balance equation Input + generation – output – consumption = accumulation Notes: 1. generation and consumption terms refer only to generation of products and consumption of reactants as a result of chemical reaction. If there is no chemical reaction then these terms are zero. 2. Apply to a system 3. Apply to total mass and component mass Paul Ashall, 2008

13. Definitions • System – arbritary part or whole of a system • Steady state/non-steady state • Accumulation/depletion of mass in system • Basis for calculation of mass balance (unit of time, batch etc) • Component or substance Paul Ashall, 2008

14. Exercise 1000 kg of a 10 % by wt. sodium chloride solution is concentrated to 50 % in a batch evaporator. Calculate the product mass and the mass of water evaporated from the evaporator. Paul Ashall, 2008

15. Mixing of streams F2 F1 F4 F3 Paul Ashall, 2008

16. Example Calculate E and x evaporator feed E, composition x% Fresh feed 1000kg, 15% by wt sodium hydrogen carbonate Recycle stream 300 kg, 10% satd. soln. Paul Ashall, 2008

17. Flowsheets • Streams • Operations/equipment sequence • Standard symbols Paul Ashall, 2008

18. Flowsheets • Process flow diagram • PID Paul Ashall, 2008

19. Typical simple flowsheet arrangement Recycle of unreacted material reactor Separation & purification product Fresh feed (reactants, solvents, reagents, catalysts etc) waste Byproducts/coproducts Paul Ashall, 2008

20. Exercise A 1000 kg batch of a pharmaceutical powder containing 5 % by wt water is dried in a double cone drier. After drying 90 % of the water has been removed. Calculate the final batch composition and the weight of water removed. Paul Ashall, 2008

21. Exercise – batch distillation 1000 kg of a 20% by wt mixture of acetone in water is separated by multistage batch distillation. The top product (distillate) contains 95% by wt. acetone and the still contains 2% acetone. Calculate the amount of distillate. Paul Ashall, 2008

22. Use of molar quantities It is often useful to calculate a mass balance using molar quantities of materials and to express composition as mole fractions or mole %. Distillation is an example, where equilibrium data is often expressed in mole fractions. Paul Ashall, 2008

23. Molar units • A mole is the molecular weight of a substance expressed in grams • To get the molecular weight of a substance you need its molecular formula and you can then add up the atomic weights of all the atoms in the molecule • To convert from moles of a substance to grams multiply by the molecular weight • To convert from grams to moles divide by the molecular weight. • Mole fraction is moles divided by total moles • Mole % is mole fraction multiplied by 100 Paul Ashall, 2008

24. Molar units Benzene is C6H6. The molecular weight is (6x12) + (6x1) = 78 So 1 mole of benzene is 78 grams 1 kmol is 78 kg Paul Ashall, 2008

25. Exercise – batch distillation 1000 kmol of an equimolar mixture of benzene and toluene is distilled in a multistage batch distillation unit. 90 % of the benzene is in the top product (distillate). The top product has a benzene mole fraction of 0.95. Calculate the quantities of top and bottom products and the composition of the bottom product. Paul Ashall, 2008

26. Mass balance - crystalliser A crystalliser contains 1000 kg of a saturated solution of potassium chloride at 80 deg cent. It is required to crystallise 100 kg KCl from this solution. To what temperature must the solution be cooled? Paul Ashall, 2008

27. Paul Ashall, 2008

28. At 80 deg cent satd soln contains (51.1/151.1)x100 % KCl i.e. 33.8% by wt So in 1000 kg there is 338 kg KCl & 662 kg water. Crystallising 100 kg out of soln leaves a satd soln containing 238 kg KCl and 662kg water i.e. 238/6.62 g KCl/100g water which is 36 g KCl/100g. So temperature required is approx 27 deg cent from table. Paul Ashall, 2008

29. Mass balance filtration/centrifuge wash water/solvent solid feed suspension filtrate waste water Paul Ashall, 2008

30. Filtration 5000 kg DM water F1 Water 300 kg API 448 kg Impurity 5 kg Impurity 55 kg Water 2600 kg API 450 kg Water 7300 kg Impurity 50 kg API 2kg Paul Ashall, 2008

31. Mass balance - drier water/evaporated solvent product feed Paul Ashall, 2008

32. Mass balance – extraction/phase split A + B A + B S + B S A – feed solvent; B – solute; S – extracting solvent Paul Ashall, 2008

33. Example (single stage extraction; immiscible solvents) feed raffinate E1 solvent extract Paul Ashall, 2008

34. F = 195 kg; xf = 0.11 kg API/kgwater S = 596 kg chloroform y = 1.72x, where y is kgAPI/kg chloroform in extract and x is kg API/kg water in raffinate. Total balance 195 + 596 = E + R API balance 19.5 = 175.5x1 + 596y1 19.5 = 175.5x1 + 596.1.72x1 x1 = 0.0162 and y1 = 0.029 R is 175.5 kg water + 2.84 kg API and E is 596 kg chloroform + 17.28 kg API Note: chloroform and water are essentially immiscible Paul Ashall, 2008

35. Mass balance – absorption unit exit gas stream feed solvent feed gas stream waste solvent stream Paul Ashall, 2008

36. Mass balances – multiple units • Overall balance • Unit balances • Component balances Paul Ashall, 2008

37. Multiple units W2 E – evaporator; C – crystalliser; F – filter unit F1 – fresh feed; W2 – evaporated water; P3 – solid product; R4 – recycle of saturated solution from filter unit R4 E C F F1 P3 Paul Ashall, 2008

38. Mass balance procedures • Process description • Flowsheet • Label • Assign algebraic symbols to unknowns (compositions, concentrations, quantities) • Select basis • Write mass balance equations (overall, total, component, unit) • Solve equations for unknowns Paul Ashall, 2008

39. Exercise A mass balance and tracking of usage of a solvent used in an API production process is required for a Pollution Emission Register (PER). Discuss and outline in general terms how you would do this. Ref. www.epa.ie Paul Ashall, 2008

40. Definitions • Stoichiometric quantities • Limiting reactant • Excess reactant • Conversion • Yield • Selectivity • Extent of reaction Paul Ashall, 2008

41. Stoichiometry • Refers to quantities of reactants and products in a balanced chemical reaction. aA + bB cC + dD i.e. a moles of A react with b moles of B to give c moles of C and d moles of D. a,b,c,d are stoichiometric quantities Paul Ashall, 2008

42. Reactor mass balances Paul Ashall, 2008

43. Example – aspirin synthesis reaction Paul Ashall, 2008

44. Limiting reactant/excess reactant • In practice a reactant may be used in excess of the stoichiometric quantity for various reasons. In this case the other reactant is limiting i.e. it will limit the yield of product(s) Paul Ashall, 2008

45. continued A reactant is in excess if it is present in a quantity greater than its stoichiometric proportion. % excess = [(moles supplied – stoichiometric moles)/stoichiometric moles] x 100 Paul Ashall, 2008

46. Example – aspirin synthesis Paul Ashall, 2008

47. Conversion • Fractional conversion = amount reactant consumed/amount reactant supplied • % conversion = fractional conversion x 100 Note: conversion may apply to single pass reactor conversion or overall process conversion Paul Ashall, 2008

48. Yield Yield = (moles product/moles limiting reactant supplied) x s.f. x 100 Where s.f. is the stoichiometric factor = stoichiometric moles reactant required per mole product Paul Ashall, 2008

49. Example – aspirin synthesis Paul Ashall, 2008

50. Selectivity Selectivity = (moles product/moles reactant converted) x s.f. x100 OR Selectivity = moles desired product/moles byproduct Paul Ashall, 2008