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Quadratic Story Problem: Projectile Height Formula

Learn how to solve quadratic story problems using the projectile height formula. Plug in given numbers to find height and time values with examples provided for better understanding.

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Quadratic Story Problem: Projectile Height Formula

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  1. At a point quadratic story problem. By Andrew Sexton Tyler Dowling Dylan Fulp

  2. The projectile height formula • H=-16t2+vot+so • You take the given numbers from the story and plug them into the formula. • H=height , t=time , v= velocity , and s= starting point.

  3. Examples • Suppose a ball is thrown from a height of 200 feet and a velocity of 100 feet per second. After how many seconds will it reach a height of 300 feet. • 300=-16t2 +96t+200. • When you put numbers into the equations the o’s are deleted. • The whole equation equals 300 because that is the height that we are trying to reach. • 100 is the velocity in which the ball was thrown so we replace the v with 96.

  4. Examples • 200 is the starting point of the ball so we replace the s with 200. • Finally the answer to how many seconds it would take would be t= 1.34 and 4.65. • To get that answer you use the quadratic equation

  5. More steps

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