1 / 25

4.2 Patterns and Linear Functions:

Dependent Variable: The variable that depends upon the value of another. 4.2 Patterns and Linear Functions:. Independent Variable: The variable that is not dependent. . Input: The values of the independent variable. Output: The values of the dependent variable.

zorana
Télécharger la présentation

4.2 Patterns and Linear Functions:

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Dependent Variable: The variable that depends upon the value of another. 4.2 Patterns and Linear Functions: Independent Variable: The variable that is not dependent. Input: The values of the independent variable. Output: The values of the dependent variable.

  2. Function  f(x): A relationship that pairs one input to exactly one output (x, y) Linear Function: A function whose graph is a nonvertical line or part of a nonvertical line.

  3. GOAL:

  4. In math we use tables, words, equations, set of ordered pairs and graphs to represent a relationship between two variables. This can be done when we are presented with the following: 1. Geometric Relationships, 2. Linear Functions

  5. GEOMETRIC RELATIONSHIPS: Ex: Use words, an equation, a table and a graph to represent the relationship between the number of rectangles and the perimeter of the figure.

  6. Words: Look at the figure, multiply the number of rectangles by 2 to get the total lengths of the top an bottom sides of the combined figure. Then add 2 times the length of the left and right sides of the combined figure to obtain the final answer for the total perimeter of the figure.

  7. Equation: Look at the figure: We must realize that the only thing that is changing is the number of the short side (width). Also, the number of the length is constant which is = 12. Using this info we see that the equation is: y or f(x) = twice the number of short + twice the length. f(x) = 2x + 12

  8. Table: Looking at the figures we see that: X = number of rectangles (independent)y = Perimeter of the figure (depends on figure)

  9. Graph: 22 20 18 Perimeter 16 14 12 10 8 6 4 2 1 4 2 3 5 Figure

  10. YOU TRY IT: Use one method to represent the relationship between the number of triangles and the perimeter. 1 1 1 1 1 1 1 1 1 1 1 1

  11. Words: Triangles = 1 Perimeter = 3 1 1 1 1 Triangles = 2 Perimeter = 4 1 1 1 1 1 1 Triangles = 3 Perimeter = 5 1 1 Look at the figure, The perimeter is 2 more than the number of triangles.

  12. Equation: Again, the perimeter [ y or f(x)] is 2 more than the number of triangles (x) y = x + 2 f(x) = x + 2

  13. Table: Looking at the figures we see that: X = number of rectangles (independent)y = Perimeter of the figure (depends on figure)

  14. Graph: 10 9 Perimeter 8 7 6 5 4 3 2 1 1 4 2 3 5 Figure Q: What is the value of y if x = 0?

  15. LINEAR FUNCTIONS:Data from a table can be scrutinize to see if it is a linear relation. In order for us to make the final decision, we first must see how the y – function, changes for each x in the table. Ex: Is there a linear relation in this table?

  16. To answer the question we must take a look at what is happening in the table. + 1 + 1 + 1 - 3 - 3 - 3 The starting memory is 512 MG The independent variable x increases by 1 The dependent variable y decreases by 3

  17. Taking the info to consideration, we can see that the equation for the problem is: + 1 + 1 + 1 - 3 - 3 - 3 y = 512 – 3x The dependent variable y decreases by 3

  18. YOU TRY IT: For the table, determine whether the relationship is a linear function. Then represent the relationship using words, an equation and a graph.

  19. YOU TRY IT: (SOLUTION) Looking at both variables, we have: +8 +1 +8 +1 +8 +1 Both, the x and y are changing at a constant rate.

  20. YOU TRY IT: (Words Solution): A person had 10 dollars and then starts a job where he earns eight dollars per hour.

  21. YOU TRY IT: (Equation Solution): We started with 10 dollars and earn 8 after each hour. y = 8x + 10 f(x) = 8x + 10

  22. YOU TRY IT: (Graph Solution) 35 30 Money $ 25 20 15 10 5 1 2 3 Hours Q: What will the total money after 4 hrs?.

  23. VIDEOS: Linear Functions https://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/analyzing-functions-algebra/v/constructing-a-linear-function-word-problem https://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/analyzing-functions-algebra/v/constructing-and-interpreting-a-linear-function

  24. CLASS WORK: Pages: 243 – 245 Problems: As many as it takes to master the concept.

  25. CLASSWORK:Page 243-245 Problems: 5, 7, 9, 11, 12, 13, 14, 16, Review Handout

More Related