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Tests of Hypotheses: Large Samples

Tests of Hypotheses: Large Samples. Chapter . Rejection region. Acceptance region. GOALS. TO DEFINE HYPOTHESES AND HYPOTHESIS TESTING. TO DESCRIBE THE HYPOTHESIS TESTING PROCEDURE. TO DISTINGUISH BETWEEN ONE-TAILED AND TWO-TAILED TEST OF HYPOTHESIS.

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Tests of Hypotheses: Large Samples

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  1. Tests of Hypotheses: Large Samples Chapter Rejection region Acceptance region

  2. GOALS • TO DEFINE HYPOTHESES AND HYPOTHESIS TESTING. • TO DESCRIBE THE HYPOTHESIS TESTING PROCEDURE. • TO DISTINGUISH BETWEEN ONE-TAILED AND TWO-TAILED TEST OF HYPOTHESIS. • TO CONDUCT A TEST FOR THE POPULATION MEAN OR PROPORTION.

  3. GOALS • TO CONDUCT A TEST FOR THE DIFFERENCE BETWEEN TWO POPULATION MEANS OR PROPORTIONS. • TO DESCRIBE STATISTICAL ERRORS ASSOCIATED WITH HYPOTHESIS TESTING.

  4. WHAT IS A HYPOTHESIS? • Hypothesis: A statement about the value of a population parameter developed for the purpose of testing. • Examples of hypotheses, or statements, made about a population parameter are: • The mean monthly income from all sources for systems analysts is $3,625. • Twenty percent of all juvenile offenders ultimately are caught and sentenced to prison.

  5. WHAT IS HYPOTHESIS TESTING? • Hypothesis testing: A procedure, based on sample evidence and probability theory, used to determine whether the hypothesis is a reasonable statement and should not be rejected, or is unreasonable and should be rejected. • Following is a five-step procedure for testing a hypothesis.

  6. State null H0 and alternative hypotheses H1 STEP 1 STEP 2 Select a level of significance STEP 3 Identify the test statistic STEP 4 Formulate a decision rule STEP 5 Take a sample , arrive at a decision Reject H0 and accept H1 Do not reject H0

  7. Null Hypothesis H0:A statement about the value of a population parameter. • Alternative Hypothesis H1: A statement that is accepted if the sample data provide evidence that the null hypothesis is false. • Level of Significance: The probability of rejecting the null hypothesis when it is actually true. • Type I Error: Rejecting the null hypothesis, H0, when it is actually true. • Type II Error: Accepting the null hypothesis, H0, when it is actually false.

  8. Researcher Null hypothesis Accepts H0 Rejects H0 Correct Decision Type I error If H0 is true and Type II error Correct Decision If H0 is false and

  9. Test statistic: A value, determined from sample information, used to determine whether or not to reject the null hypothesis. • Critical value: The dividing point between the region where the null hypothesis is rejected and the region where it is not rejected.

  10. ONE-TAILED TESTS OF SIGNIFICANCE • A test is one-tailed when the alternate hypothesis, H1, states a direction such as: • H0: The mean income of the females is less than or equal to the mean income of the males. • H1: The mean income of the females is greater than the mean income of the males. • The region of rejection in this case is to the right (upper) tail of the curve. An example is shown next:

  11. Sampling Distribution for the Statistic Z for a One-Tailed Test, 0.05 Level of Significance Critical value 1.645 = Z Region of rejection 0.95 Probability 0.05 z

  12. TWO-TAILED TESTS OF SIGNIFICANCE • A test is two-tailed when no direction is specified in the alternate hypothesis H1, such as: • H0: The mean income of the females is equal to the mean income of the males. • H1: The mean income of the females is not equal to the mean income of the males. • The region of rejection in this case is divided equally into the two tails of the curve. An example is shown next:

  13. Sampling Distribution for the Statistic Z for a Two-Tailed Test, 0.05 Level of Significance Critical value -1.96 = Z Critical value 1.96 = Z Do not reject H0 Region of rejection Region of rejection 0.95 0.025 0.025 z

  14. TESTING FOR THE POPULATION MEAN: LARGE SAMPLE, POPULATION STANDARD DEVIATION KNOWN • The test statistic is given by:

  15. EXAMPLE • The processors of Mets Catsup indicate on the label that the bottle contains 16 ounces of catsup. Mets’ Quality Control Department is responsible for monitoring the amount included in the bottle. A sample of 36 bottles is selected hourly and the contents weighed. Last hour a sample of 36 bottles had a mean weight of 16.12 ounces with a standard deviation of 0.5 ounces. At the 0.05 significance level can we conclude that the process is out of control? (i.e. not meeting weight goals)

  16. EXAMPLE (continued) • Step 1: State the null and the alternative hypotheses. • H0: m = 16 H1: m ¹ 16 • Step 2: State the decision rule. • H0 is rejected if z < -1.96 or z > 1.96.(2-side) • Step 3: Compute the value of the test statistic. • z= [16.12 - 16]/[0.05/Ö36] = 1.44. • Step 4: What is the decision on H0? • H0 is not rejected, because 1.44 is less than the critical value of 1.96.

  17. Sampling Distribution for the Statistic Z for a Two-Tailed Test, 0.05 Level of Significance Critical value -1.96 = Z Critical value 1.96 = Z Do not reject H0 Region of rejection Test Stat. 1.44 Region of rejection 0.95 0.025 0.025 z

  18. TESTING FOR THE POPULATION MEAN: LARGE SAMPLE, POPULATION STANDARD DEVIATION UNKNOWN • Here s is unknown, so we estimate it with the sample standard deviation s. • As long as the sample size n³ 30, z can be approximated with

  19. EXAMPLE • The Thompson’s Discount Store chain issues its own credit card. The credit manager wants to find out if the mean monthly unpaid balance is more than $400. The level of significance is set at 0.05. A random check of 172 unpaid balances revealed the sample mean to be $407 and the sample standard deviation to be $38. Should the credit manager conclude that the population mean is greater than $400, or is it reasonable to assume that the difference of $7 ($407 - $400) is due to chance?

  20. EXAMPLE (continued) • Step 1:State the null and the alternative hypotheses. • H0: m£ 400 H1: m > 400 • Step 2:State the decision rule. • H0 is rejected if z > 1.645. (one-sided) • Step 3:Compute the value of the test statistic. • z = [407 - 400]/[38/Ö172] = 2.42. • Step 4:What is the decision on H0? • H0 is rejected. The manager can conclude that mean unpaid balance is greater than $400.

  21. Computed z = 2.42 Rejection region 1.645 z 0

  22. HYPOTHESIS TESTING: TWO POPULATION MEANS • Assume the parameters for the two populations are m1, m2, s1, and s2. • Case I: When s1, s2 are known, the test statistic • is:

  23. HYPOTHESIS TESTING: TWO POPULATION MEANS • Case II: When s1, s2 are unknown but the sample sizes n1 and n2are greater than or equal to 30, the test statistic is :

  24. EXAMPLE • A study was conducted to compare the mean years of service for those retiring in 1975 with those retiring last year Kentucky Manufacturing Co. The following sample data was obtained. At the 0.01 significance level can we conclude that the workers retiring last year had more service?

  25. EXAMPLE (continued) • State the null and the alternative hypotheses: • Let population 2 refer to those that retired last year. H0:m2£ m1 H1:m2 > m1 • State the decision rule. • Reject H0 if z > 2.33. (one-sided) • Compute the value of the test statistic.

  26. EXAMPLE (continued) • What is the decision on the null hypothesis? Interpret the results. • Since z = 6.80 > 2.33, H0 is rejected. Those retiring last year had more years of service.

  27. TESTS CONCERNING PROPORTION • Proportion: A fraction or percentage that indicates the part of the population or sample having a particular trait of interest.

  28. TEST STATISTIC FOR TESTING A SINGLE POPULATION PROPORTION

  29. EXAMPLE • In the past 15% of the mail order solicitations for a certain charity resulted in a financial contribution. A new solicitation letter has been drafted. Will this new letter increase the solicitation rate? The new letter is sent to a sample of 200 people and 45 responded with a contribution. At the 0.05 significance level can it be concluded that the new letter is more effective?

  30. EXAMPLE (continued) • State the null and the alternative hypotheses: • H0:p£ 0.15H1:p > 0.15. • State the decision rule. • H0 is rejected if z > 1.645. (one-sided) • Compute the value of the test statistic.

  31. EXAMPLE (continued) • What is the decision on the null hypothesis? Interpret the results. • Since z = 2.97 > 1.645, H0 is rejected. The new letter is more effective.

  32. ATEST INVOLVING THE DIFFERENCE BETWEEN TWO POPULATION PROPORTIONS • The test statistic in this case is n1 is the sample size from population 1. n2 is the sample size from population 2.

  33. TWO PROPORTIONS (continued) pc is the weighted mean of the two sample proportions, computed by: X1is the number of successes in n1. X2 is the number of successes in n2.

  34. EXAMPLE • Are unmarried workers more likely to be absent from work than married workers? A sample of 250 married workers showed 22 missed more than 5 days last year for any reason. A sample of 300 unmarried workers showed 35 missed more than 5 days. Use the 0.05 significance level. • State the null and alternative hypotheses. • H0:p2£p1 H1:p2 > p1 where subscript 2 refers to the population of unmarried workers.

  35. EXAMPLE (continued) • State the decision rule. • H0 is rejected if z > 1.645. (one-sided) • Compute the value of the test statistic.

  36. EXAMPLE (continued) • What is the decision on the null hypothesis? • H0 is not rejected. There is no difference in the proportion of married and unmarried workers missing more than 5 days of work.

  37. For Final Exam Chapters 12 and 13: Regression, Inference, and Model Building/ ANOVA James S. Hawkes

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