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Key Words of the Chapter. Review (1). Entry FCC BCC HCP Coordination no. 12 8 12 Atoms in unit cell 4 2 6 One side of unit cell (a) 2R 2 4R 3 - Vc a a - Vs 4/3 πR APF (5) = Vs / Vc 0.74 0.68 0.74 ρ = wt / Vc = nA / VcNa. 3. 3. 3. Review (2). 決定結晶中之方向線或向量.
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Review (1) Entry FCCBCCHCP Coordination no. 12 8 12 Atoms in unit cell 4 2 6 One side of unit cell (a) 2R 2 4R 3 - Vc a a - Vs 4/3 πR APF (5) = Vs / Vc 0.74 0.68 0.74 ρ = wt / Vc = nA / VcNa 3 3 3
Ａ= 74.5 g/mol, R = 0.145 nm, 求密度 (ρ )? ρ = nA / Vc Na = 1 x 74.5 / 8 R x(6.023 x 10 ) = 74.5 / 8 (1.45 x 10 ) x (6.023x10 = 5.07 g/cm 3 23 3 23
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