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Pumping

Pumping. Uniform conductor: no bias, no current. length along wire. some charge shifted to left and right. length along wire. length along wire. length along wire. back to phase 1. Two parameter pumping in 1d wire. Example taken from P.W.Brouwer Phys. Rev.B 1998.

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Pumping

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  1. Pumping

  2. Uniform conductor: no bias, no current length along wire some charge shifted to left and right length along wire length along wire length along wire back to phase 1 Two parameter pumping in 1d wire Example taken from P.W.Brouwer Phys. Rev.B 1998

  3. Berry phase associated to two-parameter pumping

  4. Bouwer formulation for Two parameter pumping assuming linear response to parameters X1, X2 Circuit in parameter space There is a clear connection with the Berry phase (see e.g. Di Xiao,Ming-Che-Chang, Qian Niu cond-mat 12 Jul 2009). A circuit is not enough: one needs singularities inside. The magnetic charge that produces the Berry magnetic field is made of quantized Dirac monopoles arising from degeneracy. The pumping is quantized (charge per cycle= integer). But this is not the only kind of pumping discovered so far.

  5. time-periodic gate voltage Mono-parametric quantum charge pumping ( Luis E.F. Foa Torres PRB 2005) quantum charge pumping in an open ring with a dot embedded in one of its arms. The cyclic driving of the dot levels by a single parameter leads to a pumped current when a static magnetic flux is simultaneously applied to the ring. The direction of the pumped current can be reversed by changing the applied magnetic field (imagine going to the other side of blackboard). The response to the time-periodic gate voltage is nonlinear. The pumping is not adiabatic.No pumping at zero frequency. The pumping is not quantized.

  6. See also: Cini-Perfetto-Stefanucci,PHYSICAL REVIEW B 81, 165202 (2010) 6 6

  7. Another view of same quantum effect described above It must be possible to make all in reverse! Interaction with Bcurrent vortex->magnetic moment of ring  current in wires  Bias Bias U  current in wires vortex magnetic moment of ring Interaction with magnetic field proportional to U^3 7 This is Magnetic pumping 7

  8. Model: laterally connected ring, same phase drop on all red bonds Different distribustions of the phase drop among the bonds are equivalent in the static case, but not here. This choice is simplest. 8

  9. this is emf first clockwise then counterclockwise the ring remains excited the ring remains charged similar charge is sent to right wire charge is sent to left wire Half flux in and then out. Charging of ring with no net pumping We may avoid leaving the ring excited by letting it swallow integer fluxons 9

  10. Pumping by an hexagonal ring – insertion of 6 fluxons (Bchirality) ring returns to ground state emf always same way pumping is achieved 10

  11. Pumping by an hexagonal ring – insertion of 6 fluxons (Bchirality) effect of 6 fluxons in 200 time units Rebound due to finite leads effect of 6 fluxons in 300 time units effect of 6 fluxons in 100 time units If the switching time grows the charge decreases. It is not adiabatic and not quantized! 11

  12. What happened? We got 1-parameter pumping (only flux varies) Charge not quantized- no adiabatic result Linearity assumption fails and one may have nonadiabatic 1 parameter pumping We got a strikingly simple and general case where linearity assumption that holds in the classical case fails due to quantum effects. In the present time-dependent problem the roles of cause and effect are interchanged. 12

  13. Memory storage Insertion of 3.5 flux quanta into a ring with 17 sides connected to a junction (left wire atoms have energy level 2 in units of the hopping integral th, right wire atoms have energy level 0). The figure shows the phase pulse and the geometry. Time is in units of the inverse of the hopping integral. Right: expectation value of the ring Hamiltonian. The ring remains excited long after the pulse. It remembers.

  14. Charge on the ring . The ring remains charged after the pulse. It remembers. Fine! But memory devices must be erasable. How can we erase the memory?

  15. Same calculation as before performed in the 17-sided ring, but now with the A–B bond cut between times t = 30and t = 70. The ring energy and occupation tend to return to the values they had at the beginning, and the memory of the flux is thereby erased.

  16. Graphene Unit cell a Lower resistivity than silver-Ideal for spintronics (no nuclear moment, little spin-orbit) and breaking strength = 200 times greater than steel. a=1.42 Angstrom

  17. Corriere della sera 15 febbraio 2012

  18. the lattice is bipartite a b = basis

  19. Primitive vectors

  20. Reciprocal lattice vectors To obtain the BZ draw the smallest G vectors and the straightlinesthrough the centres of all the G vectors: the interior of the hexagonis the BZ.

  21. K’ K K M G K’ K’ K BZ and important points.

  22. K K M G K’ K’ K BZ and important points. M

  23. K K M M G K’ K’ K BZ and important points. 24

  24. Tight-binding model for the p bands: denoting by a and b the two kinds of sites the main hoppings are: b a Jean Baptiste Joseph Fourier

  25. Why 2 component? Itis the amplitude of being in sublattice a or b.

  26. (upper band)

  27. Band Structure of graphene

  28. Note the cones at K and K’ points

  29. no gap

  30. Expansion of band structure around K and K’ points

  31. Expansion of band structure around K and K’ points But the 2 components are for the 2 sublattices 35

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